There are 36 possible outcomes (6 X 6). the probability of getting a one is 1/6; the probability of getting a four is 1/6. 1/6 X 1/6 = 1/36. Then, you multiply 1/36 by 2 because you can either get a 4 and a 1 or a 1 and a 4. Therefore, the answer is:
2/36 = 1/18
The answer depends on what numbers are on the faces of the dice.
The probability that there will be EXACTLY one five when four dice are rolled is 500/1296 = 125/324, or about 38.58%. The odds are 199 to 125 against, or about 8 to 5. The probability that there will be AT LEAST one five when four dice are rolled is 671/1296, or about 51.77%. The odds are 625 to 671 against, or about 14 to 15.
3/6 chance of an odd number with one roll of the dice and 3/6 for the second roll of a dice so 3/6 x 3/6 = 9/36 = 3/12 = 1/4 there is a one in four chance that two odd numbers will be rolled from two roles of a dice.
If we are thinking of getting a '6', here are the odds. Wth one dice, its 1 in 6. So,with two dice its 1 in 216 with three dice its 1 in 7776 with four dice its 1 in 279936 with five dice its a huge 1 in 10077696
Throwing two dice, there are a total of 36 combinations (1-1, 1-2, 1-3, etc.), each of which has the same probability. Of these, the following give a sum of nine: 3-6, 4-5, 5-4, 6-3. That makes four favorable cases, or a probability of 4/36.
The probability of rolling a four on an eight sided octahedron is 1 in 8, or 0.125.
The probability of rolling a dice with the letters "D," "I," "C," and "E" on all four sides is 1 in 1,296.
The probability of rolling a three or a four (meaning one roll, and either number would be counted a "success") is 1/3. This is because the probability of rolling a three is 1/6, the probability of rolling a four is 1/6, and if you are good with either possibility, then the combined probability is 1/6+1/6 = 1/3.
There are 36 permutations of two standard dice. Of these, four have a sum of nine, specifically 3+6, 4+5, 5+4, and 6+3. The probability, then, of rolling a nine on a pair of standard dice is 4 in 36, or 1 in 9, or about 0.1111.
On a normal unbiased 6 sided dice there are 6 equally likely outcomes - 1, 2, 3, 4, 5 or 6. The probability of rolling a four is therefore 1/6.
On a normal 6 sided dice the probability of rolling any number is 1/6.When we want a 3 AND then a 4 we multiply the probabilities together.So P(3 then 4) = 1/6 x 1/6 = 1/36
The answer depends on what numbers are on the faces of the dice.
The probability is 3/6 or 1/2
The probability of rolling either a 6 or 4 on one roll of a dice is two thirds (one sixth plus one sixth because both four and six have a probability of one sixth.
It depends on the numbers on the 4 sided die. I don't believe that is a recognised standard.
The probability of rolling a four on a 6-sided die is 1 in 6, or approximately 16.67%. Since the die has 6 equally likely outcomes (the numbers 1 to 6), and only one of those outcomes is a four, the probability is 1/6.
(1 in 6)3 or (1 in 216) or about 0.004630.