There is an infinite set of numbers that fulfills this condition - all numbers of type 5n + 4, for an integer "n", for example, 4, 9, 14, 19, -1, -6, etc.
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Well, darling, when you divide any number by 5, the largest remainder you can get is 4. Why? Because when you divide by 5, the remainders can only be 0, 1, 2, 3, or 4. So, if you wanna keep it simple and sassy, the largest remainder with a divisor of 5 is 4.
To find the number, we need to consider the remainders when the number is divided by 5 and 4. Let's denote the number as x. From the information given, we have two equations: x ≡ 1 (mod 5) and x ≡ 2 (mod 4). By solving these congruences simultaneously using the Chinese Remainder Theorem, we find that x ≡ 21 (mod 20). Therefore, the number you are thinking of is 21.
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