Given that we are subtracting one square number from another and the result is 7, we can represent this mathematically as ( a^2 - b^2 = 7 ), where ( a ) and ( b ) are the square numbers. Using the difference of squares formula, we can rewrite this equation as ( (a + b)(a - b) = 7 ). Since 7 is a Prime number, the factors of 7 are 1 and 7. Therefore, the possible values for ( a ) and ( b ) are 4 and 3, respectively.
4 + 9
They are: 16 amd 9
4 and 9
9 and 1
9 and 1
when you subtract one square number with another the answer is 16 what are the two numbers
16 and 4
Let the squares be 'x' & 'y' Hence x^(2) - y^(2) = 7 Factor ( x - y)( x + y) = 7 Since '7' is a prime number, we need two number that add to '7' and subtract to '1'. They are 3, & 4 Hence (4 - 3) ( 4 + 3) = 1(7) = 7
1 and 36
That isn't possible.
4 and 3
4 + 9
Yes, that is possible.
324 - 289 = 35
16 and 25
They are: 16 amd 9
1 and 9.