4 squared is 16
2 squared is 4
The difference is 12 so the two square numbers are 4 and 16.
Solution
Let the two numbers be represented by x2 and y2, respectively. The question can be stated as:
x2 - y2 = 12
Factor the left-hand side.
(x+y)(x-y)=12
12 can be divided into the following factor pairs:
4 × 3 (where 4 = 4+0, 3+1)
6 × 2 (where 6 = 5+1, 4+2)
12 × 1 (where 12 = 7+5, 8+4, 9+3, 10+2, 11+1)
The only pair that satisfies the sum (x+y) times the difference (x-y) is 6 and 2, where (4+2)(4-2) = 12. Substituting these x and y values back into the original equation, we have:
42 - 22 = 12
16 - 4 = 12
Therefore the two numbers are 16 and 4.
4 and 9
5 and 2
They are: 16 amd 9
4 and 9
9 and 1
when you subtract one square number with another the answer is 16 what are the two numbers
4 and 9
16 and 4
5 and 2
1 and 36
9 and 25
1 and 4?
That isn't possible.
4 and 3
25 and 4 or 121 and 100
The square numbers are: 16-4 = 12
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