Let's denote the two consecutive numbers as x and x+1. The product of these two numbers is x(x+1) = 2450. This can be rewritten as x^2 + x - 2450 = 0. By factoring or using the quadratic formula, we find that the solutions are x = 49 and x = -50. Therefore, the two consecutive numbers are 49 and 50.
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The two consecutive numbers with a product of 2450 can be found by setting up the equation x(x+1) = 2450, where x is the first number. By expanding the equation, we get x^2 + x - 2450 = 0. This is a quadratic equation that can be factored as (x - 35)(x + 70) = 0. Therefore, the two consecutive numbers are 35 and 36.
34 and 35
even
The answer 2 this question is 22 and 23
The numbers are 28 and 29.