As there are two numbers, the range is the difference between them
As there are 2 numbers the mean is exactly in the middle of them.
Thus half the range is less than the mean and half the range is greater than the mean.
Thus the two numbers are 10 ± (4/2) = 10 ± 2 = 8 and 12.
Algebraically, this can be seen:
Let the two numbers be x and y with y > x
Then:
eight and twelveas mean is 10 then startwith 10 then divide the range of 4 by 2 = 2and take 2 off and add 2 on10 - 2 = 8 and 10 + 2 = 12Check:8 + 12 = 20 then divide those 2 numbers by that 2 so 20 / 2 = 10 mean12 - 8 = 4 range
To find two numbers with a mean of 10 and a range of 8, we can set up a system of equations. Let x be the smaller number and y be the larger number. We know that (x+y)/2 = 10 (mean of 10) and y-x = 8 (range of 8). Solving these equations simultaneously, we get x = 6 and y = 14. Therefore, the two numbers are 6 and 14.
four and sixteen16 - 4 = 1216 + 4 = 20 then 20 / 2 = 10Half of 12 is 6, therefore the two numbers 10 - 6 = 4 and 10 + 6 = 16 will have a mean of 10 and a range of 12.Further numbers can be added between 4 and 16 as long as their mean is still 10, eg the data sets:{4, 16}{4, 10, 16}{4, 8, 12, 16}{4, 8, 10, 12, 16}{4, 7, 9, 14, 16}all have a mean of 10 and a range of 12. There is an infinity of such sets.
To find the range of a group of numbers, subtract the smallest from the largest. examples: * range of {6, 8, 12, 19, 27} is 27 - 6 = 21 * range of {5, -2, 1, 10, 18} is 18 - (-2) = 18 + 2 = 20
mean = sum of numbers/ nos58/10=5.8
12 and 8
eight and twelveas mean is 10 then startwith 10 then divide the range of 4 by 2 = 2and take 2 off and add 2 on10 - 2 = 8 and 10 + 2 = 12Check:8 + 12 = 20 then divide those 2 numbers by that 2 so 20 / 2 = 10 mean12 - 8 = 4 range
To find five numbers with a mean of 10 and a range of 2, we first calculate the total sum of the five numbers, which would be 10 * 5 = 50. Since the range is 2, the numbers would need to be evenly spaced around the mean. One possible set of numbers could be 8, 9, 10, 11, and 12. These numbers have a mean of 10 and a range of 2.
To find two numbers with a mean of 10 and a range of 8, we can set up a system of equations. Let x be the smaller number and y be the larger number. We know that (x+y)/2 = 10 (mean of 10) and y-x = 8 (range of 8). Solving these equations simultaneously, we get x = 6 and y = 14. Therefore, the two numbers are 6 and 14.
The 3 numbers that have a mean of 10 and a median of 10.3 and a range of 2 are: 10.3, 10.85, and 8.85. These numbers add up to 30 and divided by 3 equals 10, the mean. The median, or the middle number is 10.3 because it is not as large as 10.85 but not as small as 8.85. And 10.85 minus 8.85 equals 2, or the range. Hoped this helped.... I know how hard this was I had it for homework once. :(
The mean is all of the numbers in the set of data added up then divided by how many numbers are in the set of data. It is also called the average. The range is the highest number in a set subtracted by the smallest. mean: Range: 2,4,10,and 5 2,4,10 and 4 2+4+10+4=20 10-4=6 20/4=5
The modes is the number which occurs most often. The range is the biggest number - the smallest number. The only way to have a mode of 10 and a range of 8, is to have the two numbers be 10 and 2. The numbers are different so each is a mode and the range is 10-2-8. Note, 2 is also a mode in the set {2,10}.
Oh, dude, you want to know the numbers that are 6 units apart with an average of 4? Easy peasy! Just pick any number, add 3 to it, and subtract 3 from the original number. Voila! You've got yourself a range of 6 with a mean of 4. Like, math can be fun, right?
72. (with the range of two digit numbers being from 10 to 99).
All the numbers from 10 to 99 are positive 2 digit integers
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8 and 4