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No. Since 4 is an even number, then any multiple of 4 will also be an even number. An even number will have an even digit in its ones place (0,2,4,6, or 8).
A number is a multiple of 4 if the last 2 digits are a multiple of 4 The 10s digit is even and the last digit is 0, 4 or 8 The 10s digit is odd and the last digit is 2 or 6 A number is a multiple of 8 if the last 3 digits are a multiple of 8 The 100s digit is even and the last 2 digits are a multiple of 8 The 100s digit is odd and the last 2 digits are 4 times an odd number
-3
There are an infinite number of multiples of 6 (numbers that six can divide into evenly with no remainder). Without using a calculator, you can determine if a number is a multiple of 6. To be a multiple of 6, it must have both 3 and 2 as factors. So if the number is even, then 2 is a factor. To determine if it is even, look at the ones digit, and if it is (0,2,4,6, or 8) then it's even. Then to determine if 3 is a factor, add the digits in the number, if this sum is a multiple of 3, then the number is also a multiple of 3 (or you could say 3 is a factor). If both of these are true, then the number is a multiple of 6. Example: 984: Last digit (ones digit) is 4, so it's even. Sum 9+8+4=21, which is a multiple of 3, so the number is a multiple of 3. Therefore it is a multiple of 6.