CIF is quarter screen. D1 is full. So D1 is better for viewing
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Area=ba where b=base (any side), and a=altitude, the perpendicular length from the base to the opposite sideORArea= (d1*d2)/2 where d1 is the diagonal and d2 is the other diagonal
2/3 divided by 4 is same as 2/3 divided by 4/1 As a general rule, lets take 2 ratios with their numerators being n1,n2 and denominator being d1 and d2 . So the 2 ratios are n1/d1 and n2 /d2 So if we divide the two ratios then n1/d1/n2/d2 = n1 X d2 / d1 X n2 So 2/3/4/1 = 2X1/4X3 = 2/12 = 1/6
To find out, if a number is divisible by 7, take the last digit, double it, and subtract it from the rest of the number. If you get an answer divisible by 7 (including zero), then the original number is divisible by 7.If you don't know the new number's divisibility, you can apply the rule again.Eg: Take the number 343The units digit is 3.Doubling this 3,we get 6.Subtracting 3 from 34(that is the remaining 2 digits in the number), we get 34-6=28.As 28 is divisible by 7, The whole number, i.e., 343 is divisible by 7.Proof of Divisibilty Rule for 7Let 'D' ( > 10 ) be the dividend.Let D1 be the units' digitand D2 be the rest of the number of D.i.e. D = D1 + 10D2We have to prove(i) if D2 - 2D1 is divisible by 7,then D is also divisible by 7and (ii) if D is divisible by 7,then D2 - 2D1 is also divisible by 7.Proof of (i) :D2 - 2D1 is divisible by 7 ⇒ D2 - 2D1 = 7k where k is any natural number.Multiplying both sides by 10, we get10D2 - 20D1 = 70kAdding D1 to both sides, we get(10D2 + D1) - 20D1 = 70k + D1⇒ (10D2 + D1) = 70k + D1 + 20D1⇒ D = 70k + 21D1 = 7(10k + 3D1) = a multiple of 7.⇒ D is divisible by 7. (proved.)Proof of (ii) :D is divisible by 7 ⇒ D1 + 10D2 is divisible by 7 ⇒ D1 + 10D2 = 7k where k is any natural number.Subtracting 21D1 from both sides, we get10D2 - 20D1 = 7k - 21D1⇒ 10(D2 - 2D1) = 7(k - 3D1)⇒ 10(D2 - 2D1) is divisible by 7Since 10 is not divisible by 7,(D2 - 2D1) is divisible by 7. (proved.)
Condition D is Normalized and the 1 means Black or as forged.
If the base of the box is 16X14, then the diagonal, d1 of the base is d1 =√(16)2+(14)2=√452=21.26 The diagonal of the box, d2 ,is then d2=√(21.26)2+(12)2=√595.9676=24.41 Whether the flute will fit depends upon is diameter. If the diametert is less than 0.41 inch it should fit.