-3 degrees Fahrenheit is colder.
-3
0 degree f
There are 24 possible functions: One of these is f(0) = 2 f(0.5) = 4.5 f(2) = 0.5 f(3) = 0 The four numbers in the range can be placed opposite the domain in any order.
If the terms are pairwise mappings ie f(2) = -3, f(-4) = 2 etc, then yes.
752 F
Do you mean y=3x or y=x3? I'll assume it's the latter. The first method to solving this is the easiest, the chain rule. Multiply the coefficient by the value of the exponent and reduce the exponent by 1. (f(x)=nAxn-1) You get y=3x2 Therefore, f(4)=3(42) f(4)=48 The longer method of solving this goes as follows: Your tangent formula is f'(x)=limh->0(f(x+h)-f(x))/h We know that f(x)=x3 so f(x+h)=(x+h)3 When we put this in the formula we have: f'(x)=limh->0((x+h)3-x3)/h f'(x)=limh->0((x+h)(x+h)(x+h)-x3)/h f'(x)=limh->0((x2+2hx+h2)(x+h)-x3)/h f'(x)=limh->0(x3+x2h+2x2h+2xh2+xh2+h3-x3)/h f'(x)=limh->0(3x2+3xh+h2) f'(x)=3x2+3x(0)+(02) f'(x)=3x2 And from there again we sub in 4 for x. f'(4)=3(42) f'(4)=48
-0-0
3 degrees Fahrenheit
0oF is colder
0
200 kelvin is much colder than 0 degrees F (200 kelvin = -99.67 F).
No, the higher the degree in Fahrenheit the hotter.
200 Kelvin is colder - it is -99.67 F.
0 degrees F equals -17.8C
Yes, 10°F=-12°C 20°C=68°F 10 degree Fahrenheit is colder than 20 degree Celsius. 10oF =-12.22oC which is less than 20oC .
They are the same F = 9/5 x C + 32
Yes, a constant function has degree 0; i.e., f(x)= a where a does not equal 0 is a mathematical function of degree 0. Lowell F. Lynde, Jr. (Univ. of Arkansas at Monticello)
The table shows ordered pairs for a polynomial function, f х f(x) -3 63 --2 8 -1 - 1 0 0 1 -1 2 8 3 63 What is the degree of f?
10