There are 24 possible functions: One of these is f(0) = 2 f(0.5) = 4.5 f(2) = 0.5 f(3) = 0 The four numbers in the range can be placed opposite the domain in any order.
If the terms are pairwise mappings ie f(2) = -3, f(-4) = 2 etc, then yes.
If you mean the capital letter "F" there is 3.
Do you mean y=3x or y=x3? I'll assume it's the latter. The first method to solving this is the easiest, the chain rule. Multiply the coefficient by the value of the exponent and reduce the exponent by 1. (f(x)=nAxn-1) You get y=3x2 Therefore, f(4)=3(42) f(4)=48 The longer method of solving this goes as follows: Your tangent formula is f'(x)=limh->0(f(x+h)-f(x))/h We know that f(x)=x3 so f(x+h)=(x+h)3 When we put this in the formula we have: f'(x)=limh->0((x+h)3-x3)/h f'(x)=limh->0((x+h)(x+h)(x+h)-x3)/h f'(x)=limh->0((x2+2hx+h2)(x+h)-x3)/h f'(x)=limh->0(x3+x2h+2x2h+2xh2+xh2+h3-x3)/h f'(x)=limh->0(3x2+3xh+h2) f'(x)=3x2+3x(0)+(02) f'(x)=3x2 And from there again we sub in 4 for x. f'(4)=3(42) f'(4)=48
752 F
3 degrees Fahrenheit
0 F is colder than 0 C. 0 F is equivalent to -17.8 C.
Yes, in Fahrenheit, the number is higher when it is colder. For example, 32°F is colder than 50°F.
0
200 kelvin is much colder than 0 degrees F (200 kelvin = -99.67 F).
200 Kelvin is colder - it is -99.67 F.
Yes, a constant function has degree 0; i.e., f(x)= a where a does not equal 0 is a mathematical function of degree 0. Lowell F. Lynde, Jr. (Univ. of Arkansas at Monticello)
32 degrees Fahrenheit is colder than 32 degrees Celsius. This is because the Fahrenheit scale has smaller degree intervals than the Celsius scale, so a degree change in Fahrenheit represents a greater temperature change compared to Celsius. In this case, 32 degrees Fahrenheit is equivalent to 0 degrees Celsius, so it is colder than 32 degrees Celsius.
The table shows ordered pairs for a polynomial function, f х f(x) -3 63 --2 8 -1 - 1 0 0 1 -1 2 8 3 63 What is the degree of f?
They are the same F = 9/5 x C + 32
10
3 degree Fahrenheit = -16.1 degree Celsius