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S(n)

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Q: Which notation shows that S is a function of N?
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With this radical n equals S r exponent-2 solve for r?

sqrt(n) = S*r2sqrt(n)/S = r2 sqrt(sqrt(n)/S) = ror4th root of n/sqrt(S) = r.If your equation was sqrt(n) = S*r-2sqrt(n) = S*(1/r2)sqrt(n)/S = 1/r2S/sqrt(n) = r2 sqrt(S/sqrt[n]) = rorsqrt(S)/4th root of n = r


What is the set builder notation form of 7 12 17 22 27 32 37 42 47 52?

S = {5n + 2 | n = 1, 2, ... , 10}


Scientific notation for 438 904 s?

438904 s = 4.38904×10^5 s


What is the sum of all the numbers from 1 to 1000?

well, ace of 1 (or the first number in the equation) =1, d=1 (or what it's added by each time), which shows that it's arithmetic), and n=1000 (the number you're trying to get)the equation is s of n=n/2 (ace of 1 + ace of n) s of n is the sum of the numbersso, s of n=500(1+1000)s of n=500500so 500,500 is the sum of the numbers from 1 to 1000.you can find more athttp://www.youtube.com/watch?v=VgVJrSJxkDk&feature=youtube_gdatahttp://www.youtube.com/watch?v=U_8GRLJplZg&feature=youtube_gdata


What is the sum of the first n numbers?

Assuming you mean the first n counting numbers then: let S{n} be the sum; then: S{n} = 1 + 2 + ... + (n-1) + n As addition is commutative, the sum can be reversed to give: S{n} = n + (n-1) + ... + 2 + 1 Now add the two versions together (term by term), giving: S{n} + S{n} = (1 + n) + (2 + (n-1)) + ... + ((n-1) + 2) + (n + 1) → 2S{n} = (n+1) + (n+1) + ... + (n+1) + (n+1) As there were originally n terms, this is (n+1) added n times, giving: 2S{n} = n(n+1) → S{n} = ½n(n+1) The sum of the first n counting numbers is ½n(n+1).

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