c
V1/T1 = V2/T2 T1 = 278K, T2 = 333K75 ml/278K = V2/333KV2 = (75/278K)*(333K)V2 = 89.8 ml
275K equates to 4.85C
5c =41f=278k
278km is 173 miles.
two hundred seventy-eight thousand
Use acetic anhydride as reagent. The reaction will undergo nucleophilic addition and the reagent will attach to the amine group. Half of the reagent will become the leaving group and one H of the amine group in the reactant will leave with the reagent. The product will be the benzene ring with an amine, carbonyl, methyl attached.