Substitute the value for y given by the second equation into the first equation to result in 3x - 15 = x2 - x -20. Subtract (3x - 15) from both sides and exchange sides to yield x2 - 4x - 5 = 0. This can be factored into (x - 5)(x + 1) = 0, which is true when x equals either 5 or -1. If x = 5, y = 0 and if x = -1, then y = -18. Therefore, either 5,0 or -1,-18 is an ordered pair solution to the given equation system.
Plug your ordered pair into both of your equations to see if you get they work.
That would be the "solution" to the set of equations.
The solution to a system on linear equations in nunknown variables are ordered n-tuples such that their values satisfy each of the equations in the system. There need not be a solution or there can be more than one solutions.
Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5
Tell whether the ordered pair (5, -5) is a solution of the system
7
Plug your ordered pair into both of your equations to see if you get they work.
(0,7)
That would be the "solution" to the set of equations.
an ordered pair that makes both equations true
That would depend on the given system of linear equations which have not been given in the question
x = -3/5 and y = -24/5
Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5
The solution to a system on linear equations in nunknown variables are ordered n-tuples such that their values satisfy each of the equations in the system. There need not be a solution or there can be more than one solutions.
Tell whether the ordered pair (5, -5) is a solution of the system
That of course will depend on what system of equations are they which have not been given
-1