All quadrilaterals have intersecting diagonals.
Some symmetric quadrilaterals have perpendicularly bisecting diagonals.
Equilateral parallelograms
of which the square is a special case...
and the kite where two pairs of adjacent sides are the same length has one diagonal perpendicularly bisected by the other
rhombus, kite, square
Squares, Rectangles, and Rhombuses.
trapezium
they are called parallelogram in which diagonals are equal
square
A square, a rhombus and a kite are all 4 sided quadrilaterals that have perpendicular diagonals.
If a quadrilaterl has a perpendicular diagonas it is a roumbus, also kite has perperndicular diagonals
No, the only quadrilaterals that I can think of to have perpendicular diagonals are:KiteRhombusSquare (special case of a rhombus)
Any type of rhombus has perpendicular diagonals. Please note that squares are a type of rhombus.
rhombus, kite, square
Squares, Rectangles, and Rhombuses.
They are squares and rhombuses
rhombus and a square
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Yes, the diagonals of a square are congruent (equal in length) and are perpendicular.
A parallelogram.
False. Bisecting diagonals is sufficient to guarantee a parallelogram, but the diagonals will only be perpendicular if the sides of the parallelogram are equal.