The one which has a density of 2.5 g/ml (making its volume 8 ml).
The answer depends on the temperature, but at room temperature (20 deg C), 100 ml of water would have a mass of 99.82 grams.
1 ml = 1g of water so 25ml would weight 25 grams
specific gravity of 4 4 times the mass of water, which at 50ml would weigh 50 grams.
grams
kilograms
~58 If iridium has a density of 22.42 g/cm3, 1300 grams of iridium would displace 1300/22.42 grams of water (as water has a density of 1 g/cm3). The shape of the iridium is irrelevant.
Fill a beaker with water, and weigh it. Weigh a sample of the mineral. That's the mass of the mineral. Put the sample in the beaker and weigh that. The weight of the water-filled beaker plus the weight of the mineral sample will be greater than the weight of the beaker with mineral sample and water. The difference is the weight of the displaced water, in grams. The volume of the mineral sample, in cubic centimeters is equal to the weight of the displaced water, in grams. Calculate the specific gravity of the mineral by dividing the weight of the mineral sample by the volume of the mineral sample. Example: your beaker weighs 40 grams. Filled with water, it's 1040 grams. The sample of mineral weighs 160 grams. The beaker with the sample of mineral and water weighs 1179.7 grams. The mineral, and the beaker with water would have a combined weight of 1200 grams, but the beaker with mineral and water weighs 20.3 grams less than that, so the mineral sample is displacing 20.3 cubic centimeters of water. Given a mass of 160 grams and a volume of 2.03 CC, the specific gravity would be found by dividing 160 by 20.3. It's 7.85. (Which happens to be the specific gravity of some iron.)
silver would
10 milligrams
B/ the hull would no longer displace water - as waster would be inside.
35.9 mL
The second sample is 200/10 = 20 times as large. So its mass will be 20 times as great ie 20*20 grams = 400 grams.
we can get clear water from a given sample of a muddy water by the method of decantation.
neither a sponge would
Rubidium I would not recommend, however 85.47 g will displace 197/3 = 65.67g gold ?= (14.4/65.67)x85.47
Yes
63.8g