Any substance with a density of 2.7 grams per cm3.
Aluminium and Al alloys have a density of around 2.7 gcm-3
Three times.
The Square Root of 135 is 11.61895 which if you round to the nearest tenth it would be 11.70.
To determine how many times 3 goes into 135, you would divide 135 by 3. The result is 45, meaning that 3 goes into 135 45 times. This is because when you divide 135 by 3, you are essentially asking how many groups of 3 can fit into 135 without any remainder.
To find the value that, when multiplied by 5, equals 675, you would need to divide 675 by 5. This calculation would be 675 ÷ 5 = 135. Therefore, 135 times 5 equals 675.
135÷16 = 8.4375 Or 8 times remainder 7
To calculate the density of the substance, you would divide the mass (135g) by the volume (125,000cm^3). Density = mass/volume. In this case, the density would be 0.00108 g/cm^3.
Grams can't be converted to milliliters. Grams measure mass, while milliliters measure volume.
Aluminum anything around 2.7
135mL equates to 135 cubic centimeters (cc) or0.135 cubic decimeters.
To determine the mass of one half of an aluminum (Al) cube, you first need to know the volume and density of aluminum. The density of aluminum is approximately 2.7 grams per cubic centimeter (g/cm³). If you have the volume of the entire cube, you can calculate its mass by multiplying the volume by the density, then divide that result by two to find the mass of half the cube. For example, if the cube has a volume of 100 cm³, the mass of one half would be 135 grams.
Does not convert; milligrams (mg) and grams (g) are measures of weight or mass and mL (milliliters) is a measure of volume.
135 pounds equates to 61.235kg
You need to find the density of helium in pounds per cubic foot. Then since density is mass/volume, divide the mass by the density. You may find getting the density into the units you need to use a challenge.
135/1
The **density** of a substance is defined as its mass per unit volume. We can calculate the density using the formula: [ \text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)} ] Given that the sample has a volume of **50 cm³** and a mass of **135 g**, let's determine the density: [ \rho = \frac{135 , \text{g}}{50 , \text{cm³}} ] The calculated density is approximately **2.7 g/cm³**[^10^]. Now let's compare this value to known densities: **Gold**: Gold has a density of *19.3 g/cm³*⁷. The sample's density is significantly lower. **Pure Water**: The density of pure water is approximately **1 g/cm³** at 4.0°C (39.2°F) . The sample's density is higher than water. **Aluminum**: Aluminum has a density of *2.7 g/cm³*[^10^]. The sample's density matches that of aluminum. **Ocean Water**: Ocean water contains dissolved salts, which increase its density. Seawater density typically ranges from *1.02 g/cm³ to 1.03 g/cm³*. The sample's density is higher than seawater. Based on the calculated density, the sample is most likely **aluminum**.
not soon enough, I'm sure.
138 - 135 = 3