They are 24, 25 and 26.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
29
If you've written that correctly, there aren't two whole numbers that satisfy those conditions. -20 and -5 add to -25, but multiply to 100. -25 and 4 multiply to -100, but add to -21.
119
889 898 988 997 979 799
There are hundreds of possible answers. One triplet is {101, 102, -178}.
100+25+25 = 150
They are 24, 25 and 26.
25, 27, 29
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
There are infinitely many possible sets.For example, using 2 numbers,25 + 25, 24 + 26, 23 + 27, ... 1 + 49, 0 + 50, -1 + 51, -2 + 52, ....Then you can look at numbers with 1 digit after the decimal point:24.9 + 25.1, 24.8 + 25.2, and so onNext you can look at numbers with 3 digits, 4 digits, ... , infinitely many digits after the decimal point.Then move to triplets of numbers, sets of 4 numbers, 5, 6, ... infinitely many numbers.
25 digit numbers would be septillions.
Yeah, of course you can: 25, 34, 43, 52, 61, 70
8 won't to start with. The only thing that will is 5.
the mean of four numbers is 25 and three of the numbers are 17 23 and 25 what is the fourth number?
155