Suppose the numbers are A2and B2Then A2- B2= 51
that is, (A + B)*(A - B) = 51
so A + B = 51 and A - B = 1 which gives A = 26 and B = 25
or A + B = 17 and A - B = 3 which gives A = 10 and B = 7
The square numbers are, therefore, (676, 625) or (100, 49)
Suppose the numbers are A2 and B2Then A2 - B2 = 51that is, (A + B)*(A - B) = 51so A + B = 51 and A - B = 1 which gives A = 26 and B = 25or A + B = 17 and A - B = 3 which gives A = 10 and B = 7
The square numbers are, therefore, (676, 625) or (100, 49)
Let's denote the two square numbers as (x^2) and (y^2), where (x) and (y) are integers. We are looking for two square numbers that satisfy the equation (y^2 - x^2 = 51). Using the difference of squares formula, we can rewrite this equation as ((y + x)(y - x) = 51). The factors of 51 are 1, 3, 17, and 51. By solving the system of equations (y + x = 51) and (y - x = 1), we find that the two square numbers are 676 (26^2) and 625 (25^2).
15 and 36
16 and 35
The square root of 51 is approximately 7.141. Two numbers that lie between the square root of 51 are 7 and 8. This is because 7^2 is 49, which is less than 51, and 8^2 is 64, which is greater than 51.
The answer is 39 and 19 (: hope this helps!
17 x 3= 51
15 and 36
They are 100 minus 49 = 51
the 2 numbers are 51 and 19
16 and 35
The square root of 51 is approximately 7.141. Two numbers that lie between the square root of 51 are 7 and 8. This is because 7^2 is 49, which is less than 51, and 8^2 is 64, which is greater than 51.
51 and 36
51 and 62
39 and 51
{x+y=51, x-y=26} x=38.5 y=12.5
31 and 20
To get the area, multiply the two numbers. In this case the answer is 1,275 square feet.
51 - 26 = 25; 25/2 = 12.5; 12.5 + 26 = 38.5