Suppose the numbers are A2and B2Then A2- B2= 51
that is, (A + B)*(A - B) = 51
so A + B = 51 and A - B = 1 which gives A = 26 and B = 25
or A + B = 17 and A - B = 3 which gives A = 10 and B = 7
The square numbers are, therefore, (676, 625) or (100, 49)
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Suppose the numbers are A2 and B2Then A2 - B2 = 51that is, (A + B)*(A - B) = 51so A + B = 51 and A - B = 1 which gives A = 26 and B = 25or A + B = 17 and A - B = 3 which gives A = 10 and B = 7
The square numbers are, therefore, (676, 625) or (100, 49)
Oh, dude, you're hitting me with the math questions, huh? So, let's see... well, 64 and 13 are square numbers, and their difference is indeed 51. It's like when you buy a 64-pack of crayons but only end up using 13 colors. Classic math humor, am I right?
Let's denote the two square numbers as (x^2) and (y^2), where (x) and (y) are integers. We are looking for two square numbers that satisfy the equation (y^2 - x^2 = 51). Using the difference of squares formula, we can rewrite this equation as ((y + x)(y - x) = 51). The factors of 51 are 1, 3, 17, and 51. By solving the system of equations (y + x = 51) and (y - x = 1), we find that the two square numbers are 676 (26^2) and 625 (25^2).
Well, isn't that a happy little math problem! Let's paint a picture with numbers. The square numbers that have a difference of 51 are 64 and 13. Just like painting a beautiful landscape, sometimes all it takes is a few gentle brushstrokes to reveal the hidden beauty within numbers.
Oh, what a happy little math question we have here! Let's see, if we take the square root of 51, we find that it's between the square numbers 7 and 8. The square of 8 is 64, and the square of 7 is 49. So, the square numbers that have a difference of 51 are 64 and 49.
16 and 35
The square root of 51 is approximately 7.141. Two numbers that lie between the square root of 51 are 7 and 8. This is because 7^2 is 49, which is less than 51, and 8^2 is 64, which is greater than 51.
51 3, 17
3, 17