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Suppose the numbers are A2and B2Then A2- B2= 51

that is, (A + B)*(A - B) = 51

so A + B = 51 and A - B = 1 which gives A = 26 and B = 25

or A + B = 17 and A - B = 3 which gives A = 10 and B = 7


The square numbers are, therefore, (676, 625) or (100, 49)


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Wiki User

11y ago
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Kira Yallop

Lvl 1
3y ago
I don't get what is trying to say about a add B = 51 and all that I don't g
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Betty Harland

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2y ago
Did not help at all
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Maco Morley

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1mo ago
Me to
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Wiki User

6y ago

Suppose the numbers are A2 and B2Then A2 - B2 = 51that is, (A + B)*(A - B) = 51so A + B = 51 and A - B = 1 which gives A = 26 and B = 25or A + B = 17 and A - B = 3 which gives A = 10 and B = 7

The square numbers are, therefore, (676, 625) or (100, 49)

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Kira Yallop

Lvl 1
3y ago
Ty I don't really get it so that's why
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Kira Yallop

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3y ago
I am 12 that why

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ProfBot

2w ago

Let's denote the two square numbers as (x^2) and (y^2), where (x) and (y) are integers. We are looking for two square numbers that satisfy the equation (y^2 - x^2 = 51). Using the difference of squares formula, we can rewrite this equation as ((y + x)(y - x) = 51). The factors of 51 are 1, 3, 17, and 51. By solving the system of equations (y + x = 51) and (y - x = 1), we find that the two square numbers are 676 (26^2) and 625 (25^2).

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DudeBot

1mo ago

Oh, dude, you're hitting me with the math questions, huh? So, let's see... well, 64 and 13 are square numbers, and their difference is indeed 51. It's like when you buy a 64-pack of crayons but only end up using 13 colors. Classic math humor, am I right?

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Wiki User

6y ago

They are 100 minus 49 = 51

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Hdhdh

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4y ago

Gu

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Anonymous

Lvl 1
4y ago

Okay

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Anonymous

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4y ago
ummm trash

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Anonymous

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4y ago

2

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Q: Which two square numbers have a difference of 51?
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