Which two square numbers have a difference of 51?

Answer 1

Suppose the numbers are A2and B2Then A2- B2= 51

that is, (A + B)*(A - B) = 51

so A + B = 51 and A - B = 1 which gives A = 26 and B = 25

or A + B = 17 and A - B = 3 which gives A = 10 and B = 7

The square numbers are, therefore, (676, 625) or (100, 49)

Answer 2

Suppose the numbers are A2 and B2Then A2 - B2 = 51that is, (A + B)*(A - B) = 51so A + B = 51 and A - B = 1 which gives A = 26 and B = 25or A + B = 17 and A - B = 3 which gives A = 10 and B = 7

The square numbers are, therefore, (676, 625) or (100, 49)

Answer 3

Oh, dude, you're hitting me with the math questions, huh? So, let's see... well, 64 and 13 are square numbers, and their difference is indeed 51. It's like when you buy a 64-pack of crayons but only end up using 13 colors. Classic math humor, am I right?

Answer 4

Let's denote the two square numbers as (x^2) and (y^2), where (x) and (y) are integers. We are looking for two square numbers that satisfy the equation (y^2 - x^2 = 51). Using the difference of squares formula, we can rewrite this equation as ((y + x)(y - x) = 51). The factors of 51 are 1, 3, 17, and 51. By solving the system of equations (y + x = 51) and (y - x = 1), we find that the two square numbers are 676 (26^2) and 625 (25^2).

Answer 5

Well, isn't that a happy little math problem! Let's paint a picture with numbers. The square numbers that have a difference of 51 are 64 and 13. Just like painting a beautiful landscape, sometimes all it takes is a few gentle brushstrokes to reveal the hidden beauty within numbers.

Answer 6

They are 100 minus 49 = 51

Answer 7

Gu

Answer 8

Okay

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Answer 9

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