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Anti-Stokes line is much less intense than the Stokes line. This occurs because only molecules that are vibrationally excited prior to irradiation can give rise to the anti-Stokes line. Hence, in Raman spectroscopy, only the more intense Stokes line is normally measured.

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Q: Why anti stokes line in raman spectra much weaker compared to stokes line?
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Can you perform raman spectroscopy on metals and alloys?

Yes, Raman spectra of several metals have been reported, the latest being those of uranium. Google for uranium Raman spectra for more details.


I need Database of raman spectra I have some Raman Spectra. I want to know the peaks are related with which molecule?

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What has the author Wenxin Ke written?

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What is stokes line and anti stokes line in Physics?

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What is the formula for determining wavelengths at which the the Stokes and anti-Stokes Raman lines would appear when wavenumber and wavelength of the laser are known?

ν1=1/λ1 ν1-s1


Are there different types of raman spectroscopy?

Several variations of Raman spectroscopy have been developed.· Surface Enhanced Raman Spectroscopy (SERS)· Resonance Raman spectroscopy· Surface-Enhanced Resonance Raman Spectroscopy (SERRS)· Angle Resolved Raman Spectroscopy· Hyper Raman· Spontaneous Raman Spectroscopy (SRS)· Optical Tweezers Raman Spectroscopy (OTRS)· Stimulated Raman Spectroscopy· Spatially Offset Raman Spectroscopy (SORS)· Coherent anti-Stokes Raman spectroscopy (CARS)· Raman optical activity (ROA)· Transmission Raman· Inverse Raman spectroscopy.· Tip-Enhanced Raman Spectroscopy (TERS)· Surface plasmon polaritons enhanced Raman scattering (SPPERS)


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What has the author Kirk W Brown written?

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What has the author Donald Edward Graburn Shaw written?

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What has the author Charles Alexander Bradley written?

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In Raman spectra antistock's lines are usually weaker than stock's line?

Yes, they are. anti-stockes lines are less intense than stockes at room temperature because the no. of molecules in the lowest excited vibrational level is less than that in the next higher excited vib. level... and since the intensity of the lines depends on the population of molecules.... it have weaker lines.... but at thermal equilibriume.... the no. of molecules in the next higher excited vib. level is higher than that in the lowest one....so the intensity of the anti-stockes is higher than the stockes........!!!