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let's look at log base 2 (x)=8, that means 2^x=8 so x=3 in general if b^y=x, then log base b (x)=y if the base is 1, then we have 1^y=x, but 1^y=1 for all y so it does not work..

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Q: Why can't the base on logarithms be one?
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