The short answer is: because that is what a kite is.
Long answer (although some minor steps have been skipped):
Consider a kite, ABCD, where AB = DA and BC = CD
Draw the diagonal AC.
Then triangles ABC and ACD are congruent (SSS).
So angle BAC = angle DAC.
Now draw diagonal BD which intersects AC at E.
Then triangles ABE and ADE are congruent (SAS)
So angle AEB = angle AED.
But these angles are supplementary. Therefore they must be right angles.
square and rectangle * * * * * No. Square and Kite but NOT rectangle.
A Rhombus * * * * * WRONG! A rhombus does not have equal diagonals. If it did it would be a square! The shape is a special case of a kite.
perpendicular. meaning that they make a right angle when they cross
The intersection of the diagonals of a kite form 90 degree (right) angles. This means that they are perpendicular. The longer diagonal of a kite bisects the shorter one. This means that the longer diagonal cuts the shorter one in half. It is a 4 sided quadrilateral Its 4 interior angles add up to 360 degrees It has no parallel sides Its adjacent sides are equal It has 1 pair of opposite angles that are equal It has 2 diagonals that intersect each other at right angles Its perimeter is the sum of its 4 sides Its area formula is: 0.5 times product of its diagonals
1. Opposite angles congruent 2. All sides are congruent 3. The diagonals are perpendicular bisectors of each other 4. Diagonals bisect the angles NOTE: Four congruent right triangles are formed with the right angles It has all of the properties of a parallelogram and a kite
The diagonals of a kite cross each other at right angles
kite
Yes
no, it crosses many angles 11 year Rex
A kite, a rhombus (special case of a kite), a square (a special case of rhombus).
Yes
Yes at right angles
No but its diagonals are perpendicular
Yes.
No because then it would be a square or a rectangle but a kite's diagonals meet at right angles.
Yes, they are.
Because in both cases their diagonals cross at right angles So their areas are: 0.5*product of diagonals