Look at the powers of any number, but as you'd asked, let's use 7:
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7^1 = 7
7^2 = 49
7^3 = 343
7^4 = 2,401
7^5 = 16,807
....and so on.
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To get from 7^5 to 7^4 we have to divide by 7.
16,807 divided by 7 is 2,401. (or 7^4)
And to get from 7^4 to 7^3 we have to divide by 7 again.
2,401 divided by 7 is 343 (or 7^3)
The logical idea is to continue doing this.
To go from 7^3 to 7^2 we should divide 7 again.
343 divided by 7 is 49. (or 7^2)
To go from 7^2 to 7^1 we should divide 7 yet again.
49 divided by 7 is (you guessed it) 7. (or 7^1)
Now for the ever important one. We will continue the same formula.
To get from 7^1 to 7^0, we should divide again by 7.
7 divided by 7 is.......drumroll please.......1!!!! (or 7^0!!!)
So 7^0 = 7^1 / 7 = 7/7 = 1.
This works for any nonzero number. 0^0 is undefined!!!
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I know it's confusing, but it does make sense (in theory lol) Hope I helped!!!!
Anything (except zero) to the power of zero is 1. If written as 7a0, this is operated as 7 x (a0) = 7 x 1 = 7. If written as (7a)0, it is simply 1 by the first statement.
Any number multiplied by 1 will always come out to be the original number. Any number multiplied by 0 will always equal 0. (7 x 1 = 7) (7 x 0 = 0)
1+7=8 8-7=1 1+3=4 4+3=7 7-7=0 0+7=7 7-7=0 x=0+3 the next number is 3
It is the same as 5 to the power of 7 and it equals 78125
What is the standard form for (2x+7)(x-1)=0
7^0 = 1.
Anything to the power of 0 has an answer of 1. So 7⁰ = 1, as well as any other number you can think of.
Any value to the power of 'zero' is equal; to '1' So 7^0 = 1 Similarly 7,000,000^0 = 1 Similarly 0.000007^0 = 1
75 divided by 73 = 72 by subtracting the powers Likewise 71 divided by 71 = 70 and so 7/7 = 1 Any number raised to the power 0 is always equal to 1 But any number times 0 is always equal to 0
Any negative number to the power of 0 is always -1
71 is greater.
why not !
7 -1 same as 1/7 ===
-7 to -1 : there are 7 there. +1 to +7: there are 7 there. Then there is 0. Total 15
Why is 7^0 = 1 Algebraic proof. Let 'n' be any value Let 'n be raised to the power of 'a' Hence n^a Now if we divide n^a by n^a we have n^a/n^a and this cancels down to '1' Or we can write n^(a)/n^(a) = n^(a-a) = n^(0) , hence it equals '1' Remember when the lower /denominating index is a negative power ,when raised above the division line.
(8 + 5 + 2) * (7 - 6 - 1) = 0
10-7 because if you count the 0's then that will equal 7 and how the 1 is at the end and not the 0's that makes the 7 a negative.