Well this is very self explanatory? The first top and bottom number on a dice are 6 and 1.
6 + 1 = 7
If you do this for the next two it will be 5 and 2.
5 + 2= 7
If you notice you have gone down by 1 on the high number of the dice (6 to 5) and gone up by 1 on the low number of the dice (1 to 2).
The opposite sides of dice always add up to seven, therefore your answer is six
The probability of rolling the same number on five dice is (1/6)4, or about 0.0007716.
on the dice and each opposite side eaquals 7
The total number of dots on two dice - is 42.
Yes, basically. However, dice have dots and number cubes usually have the actual numbers printed on the sides. Also, avoid saying "a dice"; that's the plural. The singular is "a die."
The opposite sides of dice always add up to seven, therefore your answer is six
Opposite faces always add to 7. Two is opposite five.
21 equals dots on a dice
There is always a 1 in 6 chance of rolling ANY number on a six-sided dice, as there are 6 numbers.
A die had 12 edges. The number of edges that dice have will depend on the number of dice!
Opposite dice sides always total 7
The answer is.... dots on a dice.
The highest number on a single "die" from a dice set is six. Therefore, the highest number available that one could roll on a dice set would be 6 multiplied by the number of dice thrown.
The lowest number will be obtained by getting lowest number on both of the dice if its a 6 sided dice (normal kind) then the lowest will be 2
The Answer Is:34/36 = 17/18 = .94444 or 94.444 %To get this Answer, You Do The Following:Find what the probability is that the SUM of 2 Dice IS 3.This means:Die 1 equals 1 & Die 2 equals 2orDie 1 equals 2 & Die 2 equals 1So ONLY 2 Variations of the Dice ALLOWS for them to SUM UP TO 3Now Determine the TOTAL number of VARATIONS (SUMMING UP TO ANYTHING):Since a Die Has 6 Sides and We need to Calculate the Variations of 2 DICE with 6 SIDES, We can Find the TOTAL NUMBER OF VARIATIONS by Doing this:TOTAL VARIATIONS FOR 2 DICE = (NUMBER OF SIDES)(NUMBER OF DICE)36 = 62Then since we know ONLY 2 Variations OUT OF ALL VARIATIONS ALLOW THE DICE TO SUM UP TO 3 we know THE PROBABILITY of the Dice Summing up to 3 is:(Number of Variations That SUM up to 3) / (TOTAL NUMBER of Variations)2 / 36 = 1 / 18 = .05556 or 5.556 %And Since We need to Determine the Probability of the Sum NOT being 3 WE need to Subtract the Probability of the DICE Summing up to 3 FROM 100% (or 36/36 = 1.00 = 100%)So To Get The ANSWER We Just Do a SIMPLE subtraction:SINCE: 100% = 1.00 = 1/1 = 36/36So We Do The Subtraction To Find WHAT PROBABILITY The SUM IS NOT 3:36/36 - 2/36 = 34/36 = 17/18 = .94444 or 94.444 %
The other side of the dice is a 2
1 in 6. Basically dice 1 can roll any number So the odds are that dice 2 has the same number as dice 1, or 1 in 6