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I think it comes from a latin word for location of position that starts with an s doctor chuck

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16y ago

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What is the position of a particle as a function of time when its velocity is given by x(6m/s)t(-2m/s2)t2?

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If f is a relation between the sets S and Twith s Є S, t Є T, and (s, t) Є f, then f is defined as a function from S into T if, and only if, s is f-related to one specific t. If this is the case, t can be expressed as a function of s via the notation t = f(s).See the related links for the definitions of relation and f-related as well as the definition of the special types of functions called metrics and sequences.


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What is the velocity of the moving object at time 5 second?

To determine the velocity of a moving object at a specific time, you would need the object's position function or acceleration function. If you have the position function, you can differentiate it to get the velocity function and then substitute t=5 seconds. If you have the acceleration function, integrate it with respect to time to get the velocity function and then substitute t=5 seconds.


What is the final position x of the object at t 18 s?

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An object is undergoing simple harmonic motion with period 1.210 s and amplitude 0.610 m. At t equals 0 the object is at x equals 0. How far is the object from the equilibrium position at time 0.485 s?

I got -0.495 m. I can't promise you this is correct, but here's my method:the position as a function of time is x(t)=A*cos(sqrt(k/m)*t)you already have A and t values, and you can solve for sqrt(k/m) by using the period they gave you.....T=2pi/(sqrt(k/m))sqrt(k/m)=2pi/TPlug and chug. Bada bing.


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The Laplace transform is a widely used integral transform in mathematics with many applications in physics and engineering. It is a linear operator of a function f(t) with a real argument t (t ≥ 0) that transforms f(t) to a function F(s) with complex argument s, given by the integral F(s) = \int_0^\infty f(t) e^{-st}\,dt.


Is it truethat a particle with a position that is given by and 119909 and 119862 and 1199052 (C is a properly dimensioned constant) has an acceleration given by 4C.?

No, the acceleration of a particle is determined by the second derivative of its position function with respect to time. If the position function is given by x(t) = 119909 + 119862t + 1199052t^2, then the acceleration a(t) would be the derivative of this function with respect to time twice, not just a constant 4C.


What is function in geometry?

It is a relationship from one set (S) to another (T) - which need not be a different set such that for every element in S there is a unique element in T.


How is constant acceleration represented on a velocity time graph?

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