answersLogoWhite

0

It is just a notation, used to make our calculations easier. Square root of -1 is undefined.

User Avatar

Wiki User

13y ago

What else can I help you with?

Related Questions

What is the value of iota?

square root of -1


Is the square root 1.6 equal to 1.6?

Square Root of 1.6 is not equal to 1.6 Example- Square Root of 1 is not equal to 1.


Square root of -1 is iota How?

Mathematicians decided that, since the square root of a negative number does not exist, they would use the first letter of "imaginary" to represent this "value".


What is the square root of -12?

The square root of 12 is: ± 3.464102


What is the value of iota square?

-1


Are they equal sin-30equals -sin30?

sin-30 = (-1) x 1/(square root of 2) -sin30 = -(1/square root of 2) They are equal


What is value of square of negative iota?

The square of negative iota will be the same as the square of positive iota (i.e. -1) because when a negative number is multiplied by a negative number, the answer is positive.


-64 square root?

The square root of -64 is 8i. ' i ' is the unit imaginary number, equal to the square root of -1, or 1 at an angle of pi/2.


What is square root of negative 2?

The square root of a negative number is considered an imaginary number. In this case, the square root of -2 is represented as √(-2) = √2i, where i is the imaginary unit equal to the square root of -1. This is because the square root of -1 is not a real number, so we introduce the concept of imaginary numbers to handle such cases in mathematics.


What is the square root of minus 8?

The square root of minus 8 is equal to the square root of 8 times the square root of minus 1, or 2.8284i.


What is the root of .1?

Finding the square root of a number is the same as saying: What number multiplied by itself is equal to the number. In this instance, the square root of 1 is equal to 1 x 1. Therefore, the square root of 1 is 1.Similarly, the cube root of 1 is also 1 (1 x 1 x 1 = 1)


What does the square root of -6 equal?

The complex pair ± 2.4495i (approx) where i is the imaginary square root of -1.