No.
The sequence increases by 7 each time and starts from 1, so the nth term is tn = 7n - 6.
If 777 is in the sequence then tn = 777 for some n that is an integer (whole number); the value of n must satisfiy 7n - 6 = 777.
7n - 6 = 777
⇒ 7n = 777 + 6
⇒ n = 111 + 6/7
⇒ n is not an integer, so 777 cannot be in the sequence.
Yes because if you divide it by 7 it will be 111
no cjjdhwi tn hjx
It will because I searched it up
31
The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...
20
46
34the sequence is11 *2= 2213 *2= 2615 *2 =30so17 *2= 3419 *2= 3821 *2= 42.......note 11,13,15,17,19,21 is a sequence that is increasing by 2 at a timeand22,26,30,34,38,42 is a sequence that is increasing by 4 at a time.===========================34Separate every other number; so ...11 13 15 17and 22 26 30so next number on top row is 19 (by adding 2 every time)and for next row add 4 every timeSo answer is 30 + 4 = 34
22
There really is no way of telling, but my guess is 22.
15% of 22 is 3.3
16 21 22 29
31
-10
22 30 39
The answer is 22. 22 - 7 = 15
The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...
4
20
22