you learn linear programming before you learn the transportation problem.
Integer programming is a subset of linear programming where the feasible region is reduced to only the integer values that lie within it.
It is a solution.
regardless of what the problem is, they are always called integers. unless you have variables or fractions in the problem.
Yes, a linear programming problem can have exactly two optimal solutions. This will be the case as long as only two decision variables are used within the problem.
Problem -> Programming Programming can be a solution to a problem. If you have a problem and it can be solved by a computer program, so you can create such a program - so you can solve this problem by programming.
An algorithm.
Integer programming is a special kind of an optimising problem where the solution must be an integer.
Solutions consist of a solvent, a liquid medium into which solutes can dissolve.
Integers are closed under subtraction, meaning that any subtraction problem with integers has a solution in the set of integers.
Yes. There need not be a feasible region.
There is no programming solution for "anything". Programs are specifically designed to solve a particular problem.
the phenomenon of obtaining a degenerate basic feasible solution in a linear programming problem known as degeneracy.
1. What do you understand by Linear Programming Problem? What are the requirements of Linear Programming Problem? What are the basic assumptions of Linear Programming Problem?
Fixed Cost Problem is a kind of the Mixed Linear Programming Problem(MILP).Also, MILP is a Parametric Quadratic Concave Programming Problem. The optimal solution is existence of vertix set of the domain set. Then, you can use the domain cutting method.
1. What do you understand by Linear Programming Problem? What are the requirements of Linear Programming Problem? What are the basic assumptions of Linear Programming Problem?
It isn't possible to solve that. The sum of three consecutive integers is always a multiple of 3 (try it out with a few small numbers); 125 is not a multiple of 3, ergo, the problem has no solution.