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To express the number 1269 as a product of prime factors, we need to find its prime factors. We start by dividing it by the smallest Prime number, which is 2. 1269 ÷ 2 = 634.5, which is not a whole number. Moving on to the next prime number, 3, we find that 1269 ÷ 3 = 423. Continuing this process, we find that 423 ÷ 3 = 141, and 141 ÷ 3 = 47. Therefore, the prime factorization of 1269 is 3 x 3 x 47.
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Blake1269 can be written as 33 x 47. It is easy to see that 3 is a factor since the sum of the digits is a multiple of 3. After you divide out the first three, you will see that 3 is a factor of the number you have left. You can do this one more time and still add the digits of the number and see that it is a multiple of 3. The number you have left after dividing by 3, three times is 47.
In general, when you want to find the prime factorization, one method is to start with the smaller primes and divide the number by those. Primes like 47 will show up at the end.
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How do write a number for example 120 as a product of its prime factors and give answers in index notation?
As a product of its prime factors: 23*3*5 = 120
How can you write 21 as a product of its prime factors?
As a product of its prime factors: 3*7 = 21
How do you write the number 198 as a product of prime factors?
198 = 2*3*3*11
Write 75 as a product of prime factors?
Prime factorization is the finding which prime number multiply to get to make the original number. Factors of 75: 1, 3, 5, 15, 25, 75 Prime factors: 3, 5 3 x 5 x 5 = 75
How do you write 125 as a product of its prime factors?
125=5x5x5
