Ksol = [Ag+]2*[CO32-] at equilibrium (saturated solution)
in which:
Note that:
As an expression it is: 5x+12
the product of 8 and the sum of 10 and -7
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How do you write an expression
3n-7
The solubility product expression for silver chromate (Ag2CrO4) is Ksp = [Ag+]²[CrO4²-], where [Ag+] represents the concentration of silver ions and [CrO4²-] represents the concentration of chromate ions in the saturated solution.
how can exponent can make it easier to write an expression with a repeated factor in the product
The expression is 9*x.
The product of nine and a
As an expression it is: 5x+12
That is called "factoring".
0.28
w(a/b)
The product of 9 and m
25x= 5
the product of 8 and the sum of 10 and -7
0.5*xy