To find the quotient when 4x^2 - 36 is divided by x - 3, you can use polynomial long division. First, divide 4x^2 by x to get 4x, then multiply x - 3 by 4x to get 4x^2 - 12x. Next, subtract 4x^2 - 12x from 4x^2 - 36 to get -12x - 36. Since -12x does not have a term with x - 3, the quotient is 4x.
X/(-3) = X + 12 X = -3X -36 4X = -36 X = -9
The x-intercept is found when "y" has no value 4x-3(0)=12 4x=12 x=3 x-int. = 3
When you're solving for the x intercept, y=0. For example, if you have a question like 3y-4x=12, and you want to find the x intercept, you substitute 0 for y. Like this: 3y-4x=12 3(0)-4x=12 -4x=12 -4x/-4=12/-4 x=-3 The x intercept is -3
3+4x=15 4x=15-3 4x=12 x=12/4 x=3 The check is: If x=3 then, 3+ (4 X 3)=15 3+12=15
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
To find the quotient when 4x^2 - 36 is divided by x - 3, you can use polynomial long division. First, divide 4x^2 by x to get 4x, then multiply x - 3 by 4x to get 4x^2 - 12x. Next, subtract 4x^2 - 12x from 4x^2 - 36 to get -12x - 36. Since -12x does not have a term with x - 3, the quotient is 4x.
If x = 3, 4x = 12
X/(-3) = X + 12 X = -3X -36 4X = -36 X = -9
The x-intercept is found when "y" has no value 4x-3(0)=12 4x=12 x=3 x-int. = 3
8
When you're solving for the x intercept, y=0. For example, if you have a question like 3y-4x=12, and you want to find the x intercept, you substitute 0 for y. Like this: 3y-4x=12 3(0)-4x=12 -4x=12 -4x/-4=12/-4 x=-3 The x intercept is -3
Depending on what sign is supposed to appear before the 4, the x-intercept is either +3 or -3 .
A = 4x + 12 = 4x + 4 × 3 = 4(x + 3)
4[x+3]=4x+12 4x+12=4x+12 it's open.
11x+9=7x+21 11x-7x=4 4x+9=21 21-9=12 4x=12 12 divided by 4= 3 x=3
x>-3 or x<3