This is a system of two linear equations:
x+2y=11
3x-4y=-17
One way to solve this system is to solve for x (or y) in the first equation and then plug it into the second equation to solve for the other variable, which then allows us to solve for our original variable.
(1) Take the first equation and solve for x: x=11-2y
(2) Plug this value into the second equation: 3x-4y=3(11-2y)-4y=33-10y=-17. We see that y=5.
(3) We now plug this into either equation to solve for x:
From (1): x=11-2y=11-2(5)=1
We get x=1 and y=5. It's also always a good idea to plug the numbers we found into our original two equations to verify they work.
Indeed, x+2y=1+2(5)=1+10=11, and
3x-4y=3(1)-4(5)=3-20=-17.
Nine plus two equals 11 and when you add six to 11 you get 17.
3h-5h + 11 = 17 is ------2h + 11 = 17- 11 -11____________-2h = 6___ ___-2 -2h = -3 (This is the answer.)
20 = 400
15b+2-13 = 13b+6-4b 15b-11 = 9b+6 15b-9b = 6+11 6b = 17 b =17/6 or 2 and 5/6
negative 11
6
17
Six
17 + 11 + (25-12) = 17 + 11 + 25 - 12 = 41.
41
-5
-17
-3z+17+12z = 11 9z = -6 z = -2/3
Nine plus two equals 11 and when you add six to 11 you get 17.
If: -2x+5 = -17 Then: x = 11
-11 + x = 17add 11 to both sidesx = 28
3h-5h + 11 = 17 is ------2h + 11 = 17- 11 -11____________-2h = 6___ ___-2 -2h = -3 (This is the answer.)