If that's x2 times 20 = 0, then x = 0, because only 0 x 20 = 0
4, -5
x2 - x = 20 x = 5
x2-x=x(x-1)=> x=0 or x=1
xy = 20 x+y=9 x=9-y y(9-y) = 20 9y-y(squared) = 20 0= y(squared)-9y+20 0= (y-5)(y-4) y= 5 or 4, x= 5 or 4 The two numbers are 5 and 4.
If that's x2 times 20 = 0, then x = 0, because only 0 x 20 = 0
20 squared = 400 = (4 x 100) + (0 x 10) + (0 x 1)
If you mean: x2+9x+20 then it is (x+4)(x+5) = 0 when factored
20 squared = 20 x 20 = 400 400 in expanded form using exponents = (4 x 10^2) + (0 x 10^1) + (0 x 10^0)
x2 = x+20 x2-x-20 = 0 (x-5)(x+4) = 0 x = 5 or x = -4
x2 - x = 20 x2 - x - 20 = 0 (x - 5)(x + 4) = 0 x - 5 = 0 and x + 4 = 0 So, x = 5 ans x = -4
(x+4)(x-5) = 0
4, -5
x2 + 9x + 20 = 0 ∴(x + 4)(x + 5) = 0 ∴x ∈ {-5, -4}
x2-35x+300 = 0 (x-15)(x-20) = 0 x = 15 or x = 20
factorise (x-5)(x+4)=0 Hence x= 5 or -4
20^2 = 400 = (4 x 100) + (0 x 10) + (0 x 1)