KE before collision =1/2 m v2 = 1/2 m (15)2= 1/2 m 225 (Velocity)2 after collision v2=u2 +2as Final velocity is 0 when object is at maximum height u is the initial velocity just after the rebound a is due to gravity = -9.8ms-2 s is the displacement = 5m 0 = u2 + 2(-9.8)5 u2=98 (ms-1)2 KE after rebound = 1/2 m 98 since mass does not change Fraction of KE remaining = 98/225 Fraction lost 1 - fraction remaining 1- (98/225) = 127/225 Not: if g is taken to be 10ms-2, then fraction is 125/225 = 4/9
The rock will have a greater speed when it reaches the ground level compared to the ball thrown horizontally because the rock will be accelerated by gravity as it falls vertically, while the ball thrown horizontally will only have its initial horizontal velocity.
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
False, provided the drop occurs no sooner than the throw, and the ground is flat .
If gravity did not affect a horizontally thrown ball, it would travel in a straight line horizontally at a constant velocity. Gravity only acts vertically, causing the ball to fall towards the ground, so without this vertical force, the horizontal motion would remain unaffected.
The distance a javelin is thrown is measured from the point where the javelin first strikes the ground to the nearest mark made by the point of the javelin that remains in the ground. The measurement is then taken in a straight line from the first mark to the throwing line.
Answer: 44 meters
Answer: 3 seconds
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
10 m/s
64 METERSA+
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
"3.2" or "3.20" please put all of that
It doesn't matter whether the object is thrown down, up, horizontally, or diagonally. Once it leaves the thrower's hand, it is accelerated downward by an amount equal to acceleration of gravity on the planet where this is all happening. On Earth, if you throw an object horizontally, it accelerates downward at the rate of 9.8 meters per second2 ... just as it would if you simply dropped it. Whether it's dropped or thrown horizontally, it hits the ground at the same time.
The rock will have a greater speed when it reaches the ground level compared to the ball thrown horizontally because the rock will be accelerated by gravity as it falls vertically, while the ball thrown horizontally will only have its initial horizontal velocity.
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
They should reach the ground together, since their initial vertical speed is the same, namely zero.