Wiki User
∙ 14y agoWell the equation D=RT is how you get the distance an object will travel in the allotted time at the rate of travel. The distance is 38, and the time is 1.7, but you don't know the rate of travel. So, D/T=R is how you find the rate of travel.
38/1.7 = 22.352 m/s horizontal velocity.
Wiki User
∙ 14y agoTo find the velocity, you can use the formula: Velocity = Distance / Time. In this case, the distance is 38 meters and the time is 1.7 seconds. So, the velocity of the Baseball thrown from third base to first base is 38 meters / 1.7 seconds = 22.35 meters per second.
If you divide the distance 38 m by the time of travel 1.7 s, then the velocity of the baseball is 22.35 m/s toward first base.
The momentum of the baseball can be calculated using the formula: momentum = mass x velocity. Plugging in the values, we get momentum = 0.148 kg x 35 m/s = 5.18 kg·m/s. So, the momentum of the baseball thrown toward home plate is 5.18 kg·m/s.
The acceleration at instantaneous maximum velocity is zero, as the velocity is not changing at that moment.
The velocity of the ball is 16 feet/sec when it is thrown upward.
The mass of the baseball thrown at 25 m/s and resulting in a momentum of 10 kg m/s is 0.4 kg. This can be calculated by dividing the momentum (10 kg m/s) by the velocity (25 m/s) of the baseball.
A baseball thrown with little velocity to fool a hitter is called a changeup. Also known as a change, changay or change-piece.
ρ=mvρ= 0.130 x 30ρ= 3.9 Kgms-1
22.35294117647059
If you divide the distance 38 m by the time of travel 1.7 s, then the velocity of the baseball is 22.35 m/s toward first base.
The momentum of the baseball can be calculated using the formula: momentum = mass x velocity. Plugging in the values, we get momentum = 0.148 kg x 35 m/s = 5.18 kg·m/s. So, the momentum of the baseball thrown toward home plate is 5.18 kg·m/s.
The ball goes up 5.1 meters.
A baseball travels under the effect of the force of gravity so its velocity is constantly changing. It is, therefore, not possible to give a sensible answer to the question.
because of 0 gravity
The acceleration at instantaneous maximum velocity is zero, as the velocity is not changing at that moment.
The velocity of the ball is 16 feet/sec when it is thrown upward.
The mass of the baseball thrown at 25 m/s and resulting in a momentum of 10 kg m/s is 0.4 kg. This can be calculated by dividing the momentum (10 kg m/s) by the velocity (25 m/s) of the baseball.
A projectile thrown with a greater velocity would travel a greater distance. Velocity is not just speed but direction as well.