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How much power is required to do 110 j of work on an object in a time of 0.6 s?
Wiki User
∙ 10y ago
183.33... Watts.
Wiki User
∙ 10y ago
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How much power is required to do 100 j of work on an object in a time of 5 how much power is required if the same work is done in 1 s?
Power is the rate at which work is done. To find the power required to do 100 J of work in 5 s, divide the work by the time: 100 J / 5 s = 20 watts. If the same work is done in 1 s, the power required would be 100 watts, as power is inversely proportional to time.
How much power is required to do 40 J of work on an object in 5 seconds?
The power required to do 40 J of work in 5 seconds is 8 watts. This can be calculated by dividing the work (40 J) by the time (5 seconds). The formula for power is Power = Work / Time.
What is the power of a machine that lifts a N object 4 in 6 seconds?
The power of the machine can be calculated using the formula Power = Work/Time. Given that Work = Force x Distance, and the force required to lift the object will be its weight (N), the power can be calculated using the force (weight of object) and the distance it is lifted in the given time frame.
How much more power is required to double an objects velocity in air?
To double an object's velocity in air, the power required increases by a factor of eight. This is because the kinetic energy of an object is proportional to the square of its velocity, so doubling the velocity means four times more power is needed. Additionally, factoring in air resistance, the actual power required may be higher due to the increased drag force at higher velocities.
How do you find the power of an object?
The power of an object is determined by the rate at which work is done on or by the object. It can be calculated by dividing the work done by the time it took to do that work. The formula for power is: Power = Work / Time.
How much power is required to do 100 j of work on an object in a time of 5 how much power is required if the same work is done in 1 s?
Power is the rate at which work is done. To find the power required to do 100 J of work in 5 s, divide the work by the time: 100 J / 5 s = 20 watts. If the same work is done in 1 s, the power required would be 100 watts, as power is inversely proportional to time.
How much power is required to do 40 J of work on an object in 5 seconds?
The power required to do 40 J of work in 5 seconds is 8 watts. This can be calculated by dividing the work (40 J) by the time (5 seconds). The formula for power is Power = Work / Time.
What is the power of a machine that lifts a N object 4 in 6 seconds?
The power of the machine can be calculated using the formula Power = Work/Time. Given that Work = Force x Distance, and the force required to lift the object will be its weight (N), the power can be calculated using the force (weight of object) and the distance it is lifted in the given time frame.
How much more power is required to double an objects velocity in air?
To double an object's velocity in air, the power required increases by a factor of eight. This is because the kinetic energy of an object is proportional to the square of its velocity, so doubling the velocity means four times more power is needed. Additionally, factoring in air resistance, the actual power required may be higher due to the increased drag force at higher velocities.
How much power does an object have that does 483.8 J of work in a time of 2 s?
The idea is to divide the work by the time.
How do you find the power of an object?
The power of an object is determined by the rate at which work is done on or by the object. It can be calculated by dividing the work done by the time it took to do that work. The formula for power is: Power = Work / Time.
It takes 200 N a box 10 meters in 8 seconds how much power is required?
First mulitiply Newton x meter to get the energy (or work) required. Then divide the result by the time to get the power.
How much is power output of a machine that lifts a 500kg object through a height of 20m in a time of 60s?
The work done by the machine would be the force required to lift the object multiplied by the distance it was lifted, which is 500kg * 9.81 m/s^2 * 20m = 98100 J. The power output would then be work done divided by time taken, which is 98100 J / 60 s = 1635 W or 1.64 kW.
How much power is required to a 110 newton object up a hall of twenty meters in eight seconds?
Since power is defined as Work divided by time, and work is F x d. W = 110 x 20 W = 2200 J P = 2200 / 8 = 275 Watts
If you do work on an object in half the time, your power output is?
If you do work on an object in half the time, your power output is twice as high. Power is the rate at which work is done, so if the time to do the work is halved, the power output is doubled to maintain the same amount of work done per unit time.
How much power is needed to perform 900 Joules of work in 90 seconds?
Power is energy per unit time. So, the required power is 900/90 = 10 Watts.
What is the time required for an object when it is traveling at the speed of light?
Time required to do what? To move from one place to another, divide the distance by the speed of light.
