Assuming the impact was elastic, Car1 will not be at rest, and Car2 will move at 20m/s at the same direction Car1 was previously moving.
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To find the final speed after the collision, you would need to consider conservation of momentum in an isolated system. If the collision is perfectly elastic, you can use the equation: m1v1i + m2v2i = m1v1f + m2v2f. With Car 2 initially at rest (v2i=0) and Car 1 moving at 20 m/s (v1i=20 m/s), you can solve for the final velocity of both cars.
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
10 m/s
The total momentum before the collision is 10,000 kg m/s (1000 kg * 10 m/s) in the direction of Car 2's initial velocity. Since the system is isolated, momentum is conserved. After the collision, the total momentum is still 10,000 kg m/s, but now shared between the two cars.
Their speed after the collision would be 5 m/s. This can be calculated using the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision in an isolated system. Since Car 1 was initially at rest (0 m/s) and Car 2 was moving at 10 m/s, their total momentum before the collision would be m * v = 1000 kg * 10 m/s = 10000 kg⋅m/s. After the collision, this total momentum would be divided between the two cars, resulting in a speed of 5 m/s for the combined system.
By conservation of momentum in an isolated system, the total momentum before the collision is equal to the total momentum after the collision. You can calculate this using the formula for conservation of momentum, which states that the initial momentum of car 2 is equal to the combined momentum of both cars after the collision. With this information, you can determine the common final speed of the two cars after the collision.