Frequence of a wave is how often a string oscillates on a specific point between crests. So if the speed of the string is lowered, the crests of the wave will pass the point less often, causing lower frequency
Yes, the density of a string affects its frequency of vibration. In general, a denser string will vibrate at a lower frequency while a less dense string will vibrate at a higher frequency when under the same tension. This relationship is described by the equation for wave speed: (v = \sqrt{\frac{T}{\mu}}), where (v) is the wave speed, (T) is the tension in the string, and (\mu) is the linear mass density of the string.
The maximum transverse speed of a particle in a string is determined by the frequency and amplitude of the wave traveling through the string. It is the highest speed at which the particle moves perpendicular to the direction of the wave.
When the wheel speed increases, the frequency also increases. This is because frequency is directly proportional to the speed of rotation of the wheel.
When frequency is high, the speed typically remains constant. This is because the speed of a wave is determined by the medium through which it is traveling, not by the frequency of the wave.
No, the fundamental frequency of a vibrating string is determined by its length, tension, and mass per unit length. The length of the string is usually equal to half the wavelength of the fundamental frequency.
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
Yes, the density of a string affects its frequency of vibration. In general, a denser string will vibrate at a lower frequency while a less dense string will vibrate at a higher frequency when under the same tension. This relationship is described by the equation for wave speed: (v = \sqrt{\frac{T}{\mu}}), where (v) is the wave speed, (T) is the tension in the string, and (\mu) is the linear mass density of the string.
Vibrations run up and down the string at the sound of speed. The longer the string the lower the frequency of the wave biting both ends, resulting in a lower pitch. Frequency is simply the frequency of the vibrations.
The maximum transverse speed of a particle in a string is determined by the frequency and amplitude of the wave traveling through the string. It is the highest speed at which the particle moves perpendicular to the direction of the wave.
When the wheel speed increases, the frequency also increases. This is because frequency is directly proportional to the speed of rotation of the wheel.
The speed changes.
speed = frequency × wave_length → frequency = speed ÷ wave_length = 1.2 m/s ÷ 60 m = 50 Hz.
When frequency is high, the speed typically remains constant. This is because the speed of a wave is determined by the medium through which it is traveling, not by the frequency of the wave.
No, the fundamental frequency of a vibrating string is determined by its length, tension, and mass per unit length. The length of the string is usually equal to half the wavelength of the fundamental frequency.
Vibrations run up and down the string at the sound of speed. The longer the string the lower the frequency of the wave biting both ends, resulting in a lower pitch. Frequency is simply the frequency of the vibrations.
The pitch is determined by by the frequency in which the string is swinging, which, in turn, is determined by the speed with which a wave can travel through the string. The higher the tension in the string is, the easier it is for a wave to travel through it, and if the speed of the wave increase, so will the frequency, and by default the pitch of the note. And vice versa. If I remember my physics correctly :)
The speed halves.