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Wave B has the higher frequency because frequency is the inverse of period. Mathematically, frequency = 1/period. Comparing the two periods, Wave B's period is smaller, so its frequency is higher.

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Q: What if your boss asks you compare two sound waves and determine which has the higher frequency. Wave A has a period of 4 and frasl100 second and Wave B has a period of 1 and frasl7 second. What would?
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What is 17 and frasl12 as a mixed number A. 1 5 and frasl12 B. 7 1 and frasl2 C. 1 12 and frasl7 D. 1 7 and frasl12?

17/12 = 1 and 5/12