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for the Doppler effect problems f0=fs((v+v0)/(v-vs) is the equation.

vs=speed of person

vo is the speed of the object

fo=the Hz the person detects

fs=Hz the object emits

v=speed of sound

in this case V0=15 m/s, fs=800Hz, v=340.6 m/s Vs=0(not stated in the problem)

f0=800Hz((340.6 m/s+15m/s)/(340.6 m/s-0))

I got f0=835.2 Hz

My teacher's answers is 837 Hz, possibly because of different rounding. I hope I did it right and explained well. Good Luck!!

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11y ago
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1mo ago

The observed frequency will be higher due to the Doppler effect. The formula to calculate the observed frequency is f' = f((v+vd)/(v-vs)), where v is the speed of sound, vd is the velocity of the detector, vs is the velocity of the source. Plugging in the values, f' = 800((340.6+15)/(340.6)). The observed frequency will be approximately 804 Hz.

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Q: What is the frequency heard by a person driving at 15m a sec toward a blowing factory whistle when f equals 800hz if the speed of sound is 340.6m a second?
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