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Assuming we neglect air resistance and start from rest in the vertical plane - use

v=u+at

so v = 0+(10x2) assuming g = 10N/kg

=20m/s

In practice it will be less because air resistance will tend to slow the skydiver down.

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βˆ™ 12y ago
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βˆ™ 7mo ago

Assuming constant acceleration due to gravity, the skydiver's downward velocity after 2 seconds can be calculated using the equation v = u + at, where v is the final velocity, u is the initial velocity (usually 0 for objects in free fall), a is the acceleration due to gravity (9.8 m/s^2), and t is the time (2 seconds). Plug the values into the equation to find the downward velocity after 2 seconds.

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Q: What is the skydiver's downward velocity after 2 seconds?
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Related questions

A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?

The velocity after 2 seconds, 5 seconds, and 10 seconds can be calculated using the formula v = gt, where g is the acceleration due to gravity (approximately 9.81 m/s^2). After 2 seconds, the velocity is 19.62 m/s downward. After 5 seconds, the velocity is 49.05 m/s downward. After 10 seconds, the velocity is 98.1 m/s downward.


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