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A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?
Since the equation for time=sqrt(2h/g) set 2 seconds for time and 9.8 for gravity so 2=sqrt(2h/9.8) clear the sqrt by squaring both sides 4= 2h/9.8 9.8*4 =2h (9.8*4)/2 = height. now that you have the height, you can do v=distance/time v=height from the equation prior/2 seconds i hope that works..
A stone falls freely from rest. What is its velocity after 8 seconds?
78.4 m/s
What is the skydivers velocity after two seconds?
We'll assume you mean 2 seconds AFTER he's jumped from the plane. A good estimate would be 9.8m/s times 2 (9.8m/s/s times 2 seconds -- the standard value of the acceleration due to gravity). In two seconds, the velocity would be low enough that air resistance could probably be ignored for purposes of answering your homework. So try 19.6 m/s, unless your teacher gave your data on the air resistance of the sky diver.
What will be the change in velocity for a 10 gram object dropped from the roof of a 20 Meter building if it takes 2 seconds to reach the ground?
Assuming the object is in free fall, the change in velocity will be approximately 19.6 m/s downward. This is calculated using the formula v = at, where acceleration due to gravity is approximately 9.8 m/s^2 and time is 2 seconds.
What is the velocity of an object that has been in free fall for 0.10 s A 0.98 m s downward B 9.8 m s downward C-9.8 m s downward D 98 m s downward?
The correct answer is B: 9.8 m/s downward. In free fall near the surface of the Earth, objects accelerate at a rate of 9.8 m/s^2 downwards due to gravity. After 0.10 seconds, the object's velocity would be 9.8 m/s downward.
A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?
Since the equation for time=sqrt(2h/g) set 2 seconds for time and 9.8 for gravity so 2=sqrt(2h/9.8) clear the sqrt by squaring both sides 4= 2h/9.8 9.8*4 =2h (9.8*4)/2 = height. now that you have the height, you can do v=distance/time v=height from the equation prior/2 seconds i hope that works..
A stone falls freely from rest. What is its velocity after 8 seconds?
78.4 m/s
What is the skydivers velocity after two seconds?
We'll assume you mean 2 seconds AFTER he's jumped from the plane. A good estimate would be 9.8m/s times 2 (9.8m/s/s times 2 seconds -- the standard value of the acceleration due to gravity). In two seconds, the velocity would be low enough that air resistance could probably be ignored for purposes of answering your homework. So try 19.6 m/s, unless your teacher gave your data on the air resistance of the sky diver.
What is the speed of an object in free fall 2 seconds after falling from rest?
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
What will be the change in velocity for a 10 gram object dropped from the roof of a 20 Meter building if it takes 2 seconds to reach the ground?
Assuming the object is in free fall, the change in velocity will be approximately 19.6 m/s downward. This is calculated using the formula v = at, where acceleration due to gravity is approximately 9.8 m/s^2 and time is 2 seconds.
What is the velocity of an object that has been in free fall for 0.10 s A 0.98 m s downward B 9.8 m s downward C-9.8 m s downward D 98 m s downward?
The correct answer is B: 9.8 m/s downward. In free fall near the surface of the Earth, objects accelerate at a rate of 9.8 m/s^2 downwards due to gravity. After 0.10 seconds, the object's velocity would be 9.8 m/s downward.
What is a skydivers velocity after 2 seconds?
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
An 8 kg mass is in free fall What is the velocity of the mass after 9 seconds?
An object dropped from rest will have a downward velocity of (9 g) = 88.2 meters per second after 9 seconds. Ignoring air resistance, the mass of the object is irrelevant. All masses fall with the same acceleration, and have the same downward velocity after any given period of time.
A penny at rest is dropped from the top of a tall stairwell what is the penny's velocity after it has fallen for 2 seconds?
it would be 7
What would be the change in velocity for a 10 gram object dropped from the roof of a 20 meter building if it takes 2 seconds to reach the ground (Hint acceleration due to gravity is 9.8 ms and sup2)?
The change in velocity of the object would be 19.6 m/s downward. This is because the object accelerates at a rate of 9.8 m/s^2 due to gravity, and after 2 seconds, it has reached a velocity of (9.8 m/s^2) * (2 s) = 19.6 m/s.
Suppose an object in free fall is dropped from a building it's starting velocity is 0 ms what is the speed (in ms) 9 the object after falling 2 seconds?
The speed of an object in free fall after 2 seconds is approximately 19.6 m/s. This speed is the result of acceleration due to gravity, which is approximately 9.8 m/s^2 downward. After 2 seconds, the velocity of the object will be equal to this acceleration times the time, resulting in a speed of 19.6 m/s.
If A ball is dropped from a rooftop what is the ball's velocity after 3 seconds?
Assuming no air resistance, the velocity of the ball after 3 seconds can be calculated using the equation v = u + gt, where v is the final velocity, u is the initial velocity (0 m/s in this case), g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time (3 seconds). Therefore, the velocity of the ball after 3 seconds would be 29.4 m/s downward.
