5*9.8 = 49 metres per second.
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The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
The rule for calculating the velocity of a falling object is V = gt, where V is the velocity, g is the acceleration due to gravity (32 ft/s^2), and t is the time in seconds. Plugging in the values: V = (32 ft/s^2) x 5 seconds = 160 ft/s. Therefore, the piano dropped 5 seconds ago is falling at a rate of 160 feet per second.
The speed of the object after falling for 3 seconds in free fall is 29.4 m/s.
The final velocity of a dropped object can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time the object has fallen. Plugging in the values, the final velocity of a dropped object after falling for 3.0 seconds would be 29.43 m/s.
The speed of an object in free fall after falling for 2 seconds is approximately 19.6 m/s. This value is obtained by multiplying the acceleration due to gravity (9.8 m/s^2) by the time the object has been falling (2 seconds).
The speed of an object in free fall after falling for 2 seconds is approximately 19.6 m/s.