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Gpe=mgh

=50*9.81*(5cos30)

=2.124kJ

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16y ago
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1mo ago

The gain in gravitational potential energy of the boy would be 2450 J. This can be calculated using the formula: ΔPE = mgh, where h is the vertical height gained. The vertical height gained can be calculated as h = L(1 - cosθ), where L is the length of the rope and θ is the angle made with the vertical (30 degrees in this case). Substituting the values, we get ΔPE = 50kg * 9.8m/s^2 * 5m * (1 - cos(30°)) = 2450 J.

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Q: What would be the gain in the gravitational potential energy of a boy when a man pulls the rope of the swing making an angle 30 degree with the vertical if mass of the boy is 50 kg and rope 5 m long?
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