You did not exactly finish your question. Are you looking for velocity, force or some sort of bounce? Velocity can be found with v2 = v1t + 1/2at2 or v2 = acceleration times distance Kinetic energy is KE= 1/2mv2
It will rise until the force of gravity on it equals the initial force used to project it upward. At that point, it will momentarily stop before falling back down due to gravity.
The speed of the rock after falling for 5 seconds would be approximately 49 m/s, neglecting air resistance. This speed is the result of the acceleration due to gravity, which is approximately 9.81 m/s^2.
A falling elephant encounters a greater force of air resistance than a falling feather does. The force of air resistance can't be greater than the weight of the falling object. When the force of air resistance is equal to the weight of the falling object, the object stops accelerating, its falling speed becomes constant, and the force of air resistance doesn't get any bigger. So the force of air resistance against a falling feather can't be greater than the weight of the feather. But the force of air resistance against a falling elephant can be, and undoubtedly is, greater than the weight of a feather.
Assuming the object is falling near the surface of the Earth and neglecting air resistance, the object will fall approximately 4.9 meters in 1 second. This calculation is based on the acceleration due to gravity, which is approximately 9.8 meters per second squared.
An object falling freely near Earth's surface without air resistance follows the acceleration due to gravity, which is approximately 9.81 m/s^2. This means its speed increases by 9.81 m/s every second, regardless of its mass. In the absence of air resistance, objects of different masses will fall at the same rate in a vacuum.
Neglecting air resistance his velocity after 1 second will be 9.81 m/sec or 32.2 ft/sec.
The object will be falling at 49 m/s.This is solved by multiplying the force of gravity (9.8 m/s) by the time you're calculating (5s).
Neglecting the effect of air resistance, the speed of any falling object ... including ice cubes ... is always 32.2 feet per second greater than it was one second earlier.
The speed at which a 200 pound man falls from a 3-story building would be approximately 53 meters per second when neglecting air resistance. This speed is calculated using the formula v = sqrt(2gh), where v is the final velocity, g is the acceleration due to gravity (9.81 m/s^2), and h is the height of the building (around 9 meters for a 3-story building).
It will rise until the force of gravity on it equals the initial force used to project it upward. At that point, it will momentarily stop before falling back down due to gravity.
The speed of the rock after falling for 5 seconds would be approximately 49 m/s, neglecting air resistance. This speed is the result of the acceleration due to gravity, which is approximately 9.81 m/s^2.
A falling elephant encounters a greater force of air resistance than a falling feather does. The force of air resistance can't be greater than the weight of the falling object. When the force of air resistance is equal to the weight of the falling object, the object stops accelerating, its falling speed becomes constant, and the force of air resistance doesn't get any bigger. So the force of air resistance against a falling feather can't be greater than the weight of the feather. But the force of air resistance against a falling elephant can be, and undoubtedly is, greater than the weight of a feather.
it is a blizzard
Blizzard
distance = 1/2 g t^2 = 1/2 x 32.2 x 5 x 5 = 405 feet (neglecting air resistance)
Air resistance creates friction and slows a falling object.
It reduces the acceleration of the falling object due to friction.