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Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
Wiki User
∙ 9y ago
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
Wiki User
∙ 9y ago
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Determine the magnitude and direction of F so that the particle is in equilibrium?
To have equilibrium, the net force acting on the particle must be zero. The magnitude of force F must be equal in magnitude (but opposite in direction) to the resultant of all other forces acting on the particle. Therefore, to determine F, you need to calculate the vector sum of all other forces acting on the particle and then determine the magnitude and direction for F.
If the acceleration of a particle is constant in magnitude but not in direction what type of path the particle follow?
If the acceleration of a particle is constant in magnitude but not in direction, the particle will follow a curved path. The changing direction of the acceleration will cause the particle to continually change its velocity vector, resulting in curved motion.
Can particle with constant velocity be accelerating?
No. Velocity implies both a magnitude and a direction.No. Velocity implies both a magnitude and a direction.No. Velocity implies both a magnitude and a direction.No. Velocity implies both a magnitude and a direction.
What is the translational speed of the particle at point a?
The translational speed of a particle at a point is the magnitude of the particle's velocity vector at that point. It is given by the derivative of the position vector with respect to time evaluated at that point.
In addition to the distance from a charged particle what other factor determines the magnitude of the electric potential?
Another factor that determines the magnitude of the electric potential is the amount of charge on the particle creating the electric field. The electric potential is directly proportional to the charge creating the field.
How is motion of charged particle parallel to unifrom electric field is equivalent to the body falling freely under gravity?
If the charge of the particle is such that it is attracted to the E-field then it's motion is analogous to gravitational free fall in a couple of ways. - Both forces have no horizontal component, therefore no horizontal acceleration. - Both forces interact at a magnitude inversely proportional to the square of their distance. - In both cases, Newton's third law applies, despite the nearly unmeasurable effects that the particle/body has on the field/earth.
A particle is projected at 60 degree to the horizontal with a kinetic energy k the kinetic energy at highest point is?
At the highest point of the particle's trajectory, its kinetic energy will be zero because it momentarily comes to a stop at that point. Potential energy will be at a maximum at this point.
How you calculate the kinetic energy of the particle projected vertically upwards?
The kinetic energy of a particle projected vertically upwards can be calculated using the formula: KE = 1/2 * m * v^2, where m is the mass of the particle and v is the velocity at which it is projected upwards. The kinetic energy is the energy associated with the motion of the particle.
Determine the magnitude and direction of F so that the particle is in equilibrium?
To have equilibrium, the net force acting on the particle must be zero. The magnitude of force F must be equal in magnitude (but opposite in direction) to the resultant of all other forces acting on the particle. Therefore, to determine F, you need to calculate the vector sum of all other forces acting on the particle and then determine the magnitude and direction for F.
What happens to a particle when heated?
The magnitude of the vibration of its molecules gets increased.
If the acceleration of a particle is constant in magnitude but not in direction what type of path the particle follow?
If the acceleration of a particle is constant in magnitude but not in direction, the particle will follow a curved path. The changing direction of the acceleration will cause the particle to continually change its velocity vector, resulting in curved motion.
What is the relation of the time in the air to the height reached with a constant horizontal distance and applied force?
I am assuming that this is to do with the trajectory that is simplified to that of a particle which does not incur air resistance. If I have understood the question correctly, the particle travels under the influence of a constant force - assumed to be gravity which acts downwards. The model can be extended to allow for a constant force acting at an angle but the calculations then become more complicated. The particle is projected upwards, with the initial velocity, u ms-1, which makes an angle P with the horizontal. u is a variable such that the horizontal range of the particle is a constant. The vertical component of the initial velocity is u*sin(P) ms-1. The gravitational force, acting downwards, is -g ms-2. When the particle returns to the ground level, the vertical component of its velocity is -u*sin(P) ms-1. So if the particle returns at time t seconds, then t = [u*sin(P) - -u*sin(P)] /g = 2*u*sin(P)/g sec. The horizontal component of the velocity of the particle is a constant u*cos(P) ms-1. So during the time in flight, it travels u*cos(P)*2*u*sin(P)/g m = 2*u2*sin(P)*cos(P)/g m. This horizontal distance is constant, which implies that 2*u2*sin(P)*cos(P)/g is constant so that u2 is inversely proportional to sin(P)*cos(P). So let u = sqrt[k/sin(P)*cos(P)] ms-1 for some constant k. then its vertical component is u*sin(P) = sqrt[k/sin(P)*cos(P)]*sin(P) ms-1 = sqrt[k*tan(P)] Then at time T, its height is sqrt[k*tan(P)]*T - 0.5g*T2 I just hope this is correct!
Can particle with constant velocity be accelerating?
No. Velocity implies both a magnitude and a direction.No. Velocity implies both a magnitude and a direction.No. Velocity implies both a magnitude and a direction.No. Velocity implies both a magnitude and a direction.
What is the relationship between porosity bulk density and particle density?
If you were to graph particle size and porosity, it would be a constant slope (horizontal line).Porosity is not affected by particle size.
What is the translational speed of the particle at point a?
The translational speed of a particle at a point is the magnitude of the particle's velocity vector at that point. It is given by the derivative of the position vector with respect to time evaluated at that point.
If the acceleration of a particle is constant in magnitude but not in direction what type of path the particle follows?
You are mad 😂😂 you don't know this much easy answer 😆😆
In addition to the distance from a charged particle what other factor determines the magnitude of the electric potential?
Another factor that determines the magnitude of the electric potential is the amount of charge on the particle creating the electric field. The electric potential is directly proportional to the charge creating the field.
