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How do you solve b plus 9 equals 2?
b+9=2 sbtract nine both sides b=2-9 b=-7
The width of rectangle is 5 feet and the diagonal is 9 feet what is the area of the rectangle?
a^2+b^2=c^2 a=5 c=9 5^2+b^2=9^2 25+b^2=81 b^2=56 b=7.5 Therefore, the width is 5ft and the length is 7.5ft. The area=5 x 7.5=37.5
If the sum of two numbers is 18 and the product is 45 what are those two numbers?
15 and 3--a + b = 18a = 18 - ba * b = 45(1-b)*b = 4518b-b^2 = 45b^2-18b = -45b^2-18b+81 = 36(b-9)^2 = 6^2b-9 = +/-6b = 9+/-6 = 3, 15a = (18 -b ) = 18 - 9 +/- 6a = 15, 3
A plus b equals 8 and a minus b equals 9?
Solve one of the formulas for A, then substitute that into the other formula to solve for B, then substitute the solution for B into one of the formulas to solve for A. Here is how: Givens: A+B=8 A-B=9 So: If A+B=8 then A=8-B Next, substitute this into the other formula... A-B=9 (8-B)-B=9 (-B) - B = 1 (-2B) = 1 B= (- 1/2) Next, substitute the solution for B into one of the formulas to solve for A.... A+B=8 A+ (-1/2) = 8 A = 8 and 1/2 So... B= (- 1/2) A = 8 and 1/2
How would you factor 18b plus 9?
18b+9 = 9(b+2)
How do you solve b plus 9 equals 2?
b+9=2 sbtract nine both sides b=2-9 b=-7
What is the possible area of a rectangle when one side is 9m and the perimeter is 30m?
Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.
Is a to the second power over b to the second power greater than a over b?
Let's reverse the question - Is a over b less than a squared over b squared? Answer - Only when a is less than b example 1: a is less than b a = 2 a squared = 4 b = 3 b squared = 9 2 / 3 = .6666 4 / 9 = .444444 2 / 3 is greater than 4 / 9 example 2: a is equal to b a = 2 a squared = 4 b = 2 b squared = 4 2 / 4 = .5 2 / 4 = .5 2 / 4 is equal to 2 / 4 example 3: a is greater than b a = 3 a squared = 9 b = 2 b squared = 4 3 / 2 = 1.5 9 / 4 = 2.25 3 / 2 is less than 9 / 4 - wjs1632 -
The width of rectangle is 5 feet and the diagonal is 9 feet what is the area of the rectangle?
a^2+b^2=c^2 a=5 c=9 5^2+b^2=9^2 25+b^2=81 b^2=56 b=7.5 Therefore, the width is 5ft and the length is 7.5ft. The area=5 x 7.5=37.5
What is the solution for B2 plus 2b-11 equals 88?
If this was b exponent 2 (squared) or b^2 for the first b, then it is a quadratic expression. b^2 + 2b - 11 = 88 b^2 + 2b - 99 = 0 (b+11)(b-9) = 0 B = -11 or 9
How do you answer 9 plus b squared equals 11?
9+b2=11 b2=11-9=2 b=positive or negative sqrt(2)
What algebraic expression shows the square of the distance from point A to point B minus 81?
(B - A)2 - 81 or (B - A + 9)(B - A - 9) If the starting point, A, is taken as zero the the expression simplifies to (B + 9)(B - 9)
If the sum of two numbers is 18 and the product is 45 what are those two numbers?
15 and 3--a + b = 18a = 18 - ba * b = 45(1-b)*b = 4518b-b^2 = 45b^2-18b = -45b^2-18b+81 = 36(b-9)^2 = 6^2b-9 = +/-6b = 9+/-6 = 3, 15a = (18 -b ) = 18 - 9 +/- 6a = 15, 3
A plus b equals 8 and a minus b equals 9?
Solve one of the formulas for A, then substitute that into the other formula to solve for B, then substitute the solution for B into one of the formulas to solve for A. Here is how: Givens: A+B=8 A-B=9 So: If A+B=8 then A=8-B Next, substitute this into the other formula... A-B=9 (8-B)-B=9 (-B) - B = 1 (-2B) = 1 B= (- 1/2) Next, substitute the solution for B into one of the formulas to solve for A.... A+B=8 A+ (-1/2) = 8 A = 8 and 1/2 So... B= (- 1/2) A = 8 and 1/2
Factor 18b plus 9?
18b+9=9(b+2)
10b - 9 if b 2?
11
How would you factor 18b plus 9?
18b+9 = 9(b+2)
