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How do you solve b plus 9 equals 2?
b+9=2 sbtract nine both sides b=2-9 b=-7
The width of rectangle is 5 feet and the diagonal is 9 feet what is the area of the rectangle?
a^2+b^2=c^2 a=5 c=9 5^2+b^2=9^2 25+b^2=81 b^2=56 b=7.5 Therefore, the width is 5ft and the length is 7.5ft. The area=5 x 7.5=37.5
If the sum of two numbers is 18 and the product is 45 what are those two numbers?
15 and 3--a + b = 18a = 18 - ba * b = 45(1-b)*b = 4518b-b^2 = 45b^2-18b = -45b^2-18b+81 = 36(b-9)^2 = 6^2b-9 = +/-6b = 9+/-6 = 3, 15a = (18 -b ) = 18 - 9 +/- 6a = 15, 3
A plus b equals 8 and a minus b equals 9?
Solve one of the formulas for A, then substitute that into the other formula to solve for B, then substitute the solution for B into one of the formulas to solve for A. Here is how: Givens: A+B=8 A-B=9 So: If A+B=8 then A=8-B Next, substitute this into the other formula... A-B=9 (8-B)-B=9 (-B) - B = 1 (-2B) = 1 B= (- 1/2) Next, substitute the solution for B into one of the formulas to solve for A.... A+B=8 A+ (-1/2) = 8 A = 8 and 1/2 So... B= (- 1/2) A = 8 and 1/2
How would you factor 18b plus 9?
18b+9 = 9(b+2)
