9a + 3b - 11a - 4b = -2a -b
3(3a+b)
a = 6b = 9a + b = 6 + 9 = 15
The given terms can be simplified to: a -b
18a3bc
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
4b.
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
4b
b+b+b+c+c+c+c =3b+4c
b + b + b + c + c + c + c = 3b + 4c
a-b+a-b+2b+a = 4a