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Al Leuschke

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4y ago

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Related Questions

What is 2369 divide by 26?

91.1154


What is 3 over 26 simplified?

3/26 is in its most simplified form . Reason , there are no common factors between '3' and '26'.


Is 3 a factor of 26?

No. A factor of a number divides it evenly.When you try to divide 26 by 3, you get a remainder of 2. That means 3 is not a factor.


What is 26 and divide 5278?

26 and divide 5278 = 0.0049261083743842365


What is the aspect ratio of the image on SDTV?

Typically, it is 4:3. As an example: 26" across the screen and 19.5" down. If you divide 19.5 by 3 you get 6.5; then, if you divide 26 by 6.5, you get 4. So, dividing both 26 and 19.5 by 6.5, you get 4 and 3; hence, the 4:3 designation (nothing magic about 6.5--it is simply the divisor which reduces the 26 and 19.5 to lowest possible integers.)


What is the average of 24 26 and 31?

31 + 26 + 24 = 81 / 3 = 27 To find the above average, add the the three numbers together, then divide by 3


Could 3 be divided by 26?

0.1154


How many times will 3 go into 26?

To determine how many times 3 will go into 26, we perform division. When we divide 26 by 3, we get 8 with a remainder of 2. Therefore, 3 will go into 26 eight times evenly, with a remainder of 2.


What is 3 divide 78 equal?

0.0385


How do you divide 7903 dived by 26?

To divide 7903 by 26, you would perform long division. Start by dividing 79 by 26, which equals 3 with a remainder of 1. Bring down the next digit, 0, to the remainder to make it 10. Then divide 10 by 26, which equals 0 with a remainder of 10. Finally, bring down the last digit, 3, to the remainder to make it 103. Dividing 103 by 26 gives you 3 with a remainder of 25. Therefore, 7903 divided by 26 equals 303 with a remainder of 25.


What is 12 divided 104?

8.6667


To prove cube root of 26 is irrational?

The proof is by the method of reductio ad absurdum. We start by assuming that cuberoot of 26, cbrt(26), is rational. That means that the cube root can be expressed in the form p/q where p and q are co-prime integers. That is, cbrt(26) = p/q.Therefore, p^3/q^3 = 26 which can also be expressed as 26*q^3 = p^3 Now 26 = 2*13 so 2 divides the left hand side (LHS) and therefore it must divide the right hand side (RHS). That is, 2 must divide p^3 and since 2 is a prime, 2 must divide p. That is p = 2*r for some integer r. Then substituting for p gives, 26*q^3 = (2*r)^3 = 8*r^3 Dividing both sides by 2 gives 13*q^3 = 4*r^3. But now 2 divides the RHS so it must divide the LHS. That is, 2 must divide q^3 and since 2 is a prime, 2 must divide q. But then we have 2 dividing p as well as q which contradicts the requirement that p and q are co-prime. The contradiction implies that cbrt(26) cannot be rational.