2x + y = 7
y = x + 1
This is a simple linear system of equations, to solve it re-order and eliminate terms to solve for a single and then substitute back into the main equation
rewrite y = x + 1 as x - y = -1
eliminate y
(2x + y = 7) + (x - y = -1) = (3x = 6)
from this x = 2, plugging back into the first equation produces y = 3
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if: 2x + 6 = -6 then: 2x = -12 x = -6 if: 5x + 7y = 1 then: 5(-6) + 7y = 1 7y = 31 y = 31/7
10x-7y=-110x+1=7y-2x -10x-1=-25-12x-1=-25-12x=-24x=-24/-12x=210(2)-7y=-120-7y=-121=7y21/7=yy=3
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
7y-8 = 6y+1 7y-6y = 1+8 y = 9
-2x plus 3y equals 1