2x + y = 7
y = x + 1
This is a simple linear system of equations, to solve it re-order and eliminate terms to solve for a single and then substitute back into the main equation
rewrite y = x + 1 as x - y = -1
eliminate y
(2x + y = 7) + (x - y = -1) = (3x = 6)
from this x = 2, plugging back into the first equation produces y = 3
if: 2x + 6 = -6 then: 2x = -12 x = -6 if: 5x + 7y = 1 then: 5(-6) + 7y = 1 7y = 31 y = 31/7
10x-7y=-110x+1=7y-2x -10x-1=-25-12x-1=-25-12x=-24x=-24/-12x=210(2)-7y=-120-7y=-121=7y21/7=yy=3
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
7y-8 = 6y+1 7y-6y = 1+8 y = 9
the answer to this problem is -2x^2y^2
if: 2x + 6 = -6 then: 2x = -12 x = -6 if: 5x + 7y = 1 then: 5(-6) + 7y = 1 7y = 31 y = 31/7
10x-7y=-110x+1=7y-2x -10x-1=-25-12x-1=-25-12x=-24x=-24/-12x=210(2)-7y=-120-7y=-121=7y21/7=yy=3
6x+7y=-6 3(-2x-3y=2) +________ -2y=0 => y=0 Therefore x=-1
If you mean: 2x+7y = -1 and 4x-3y = -19 then by substitution x = -4 and y = 1
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
7y-8 = 6y+1 7y-6y = 1+8 y = 9
y=5.
x=1
x = 0
the answer to this problem is -2x^2y^2
-2x plus 3y equals 1
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5