4 square root of -9 = 4 square root of (-1)(9) = 4 square root of (i29) = 4(3i) = 12i
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9 square root 4 minus 12 square root 4 = -6
no, it is actually not a real number. It falls under the category of a imaginary number which is the square root of -1 or as the variable i Because the square root of -4 is 2i because the square root of 4 is 2 and if you take i out it will maek it a positive so it goes like this -4 SR= 2i -9 square root= 3i and so on
9
sqrt(16/9) = sqrt(16) / sqrt(9) = 4/3 .That's the square root of positive 16/9. There is no square root of a negative number, unlessyou want to get into what's called "imaginary" numbers in math and engineering.If you want the square root of -(16/9), or (-16)/9, or 16/(-9), in each case it's (4/3)i .That little ' i ' is the unit imaginary number, defined as the square root of (-1).That's probably as far into it as we ought to go for right now.
The square roots of -81 are ±9i where i is the imaginary square root of -1.