6300 writen as products of primes?

Answer 1

You can factor this easily, if you start with some obvious factors. For a start, each zero at the end represents the prime factors 2 x 5.That leaves you with 2 x 5 x 2 x 5 x 63; next, start looking for small factors for the number 63 (in this case, it is divisible by 3).

Answer 2

2^2 x 3^2 x 5^2 x 7 = 6300